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RoseWind [281]
3 years ago
14

Help me with this question

Mathematics
1 answer:
Vlad [161]3 years ago
8 0
Man why you asking us like we know
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What's the interest rate of $7,000 at 3% ​
den301095 [7]

Answer:

Beginning Balance; Interest Payment; Principal Payment

$7,000.00                            $17.50              $283.37

Step-by-step explanation:

i hope this help

7 0
3 years ago
Whats the answer to this?​
kramer

ZillaKami:

Ghostemane

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3 years ago
{x}^{2}-10x+21=0x<br> Solve and explain step by step <br> thanks
Alex73 [517]

Answer:

x = 3,7

Step-by-step explanation:

x² - 10x + 21 = 0

x² - 7x - 3x + 21 = 0

x(x - 7) - 3(x - 7) = 0

(x - 3)(x - 7) = 0

x = 3, 7

Means the graph cuts the x-axis at 3 and 7

3 0
4 years ago
Read 2 more answers
what is an equation in point-slope form of the line that passes through the given point and with the given slope m (-5,1);m=4
zalisa [80]

Equation for line: y=mx+b where m is the slope and b is the y-intercept

We have the slope. We just need to find the y-intercept. Plug in the point and the slope and solve for b.

y=mx+b

1=4(-5)+b

b=21

Answer: y=4x+21

6 0
3 years ago
√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
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