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3 years ago

Plz help I need help with this question

Mathematics

1 answer:

defon3 years ago

3 0

Answer:

This would be C because the others are all 4 units apart making the line segments 4 units long

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Help with word problem!

creativ13 [48]

2 1/6 divided by 7/10

13/6 / 7/10 =

13/6 * 10/7 =

130/42 =

3 4/42. or 3 2/21 hours... three and two twenty-firsts

7 0

3 years ago

Mrs galvan's truck averages 24.94 miles per gallon of gasoline. His gasoline tank holds a maximum of 25 gallons. How far could M

ch4aika [34]

Answer: He could drive 623.5 miles on a full tank of gasoline

Step-by-step explanation:

6 0

3 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago

Solve 5x^2-2=-12 by taking the square root

k0ka [10]

Answer:

x = ±i√2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality

Division Property of Equality

Addition Property of Equality

Subtraction Property of Equality

Algebra II

Imaginary root i

i = √-1

Step-by-step explanation:

Step 1: Define

Identify

5x² - 2 = -12

Step 2: Solve for x

[Addition Property of Equality] Add 2 on both sides: 5x² = -10
[Division Property of Equality] Divide 5 on both sides: x² = -2
[Equality Property] Square root both sides: x = ±√-2
Rewrite: x = ±√-1 · √2
Simplify: x = ±i√2

7 0

3 years ago

Please solve its URGENT

ZanzabumX [31]

The answer is X= -25

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3 years ago