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Anon25 [30]
2 years ago
11

How many moles are in 25.90 grams of NaCl

Chemistry
1 answer:
inessss [21]2 years ago
7 0

Answer:

0.44316859040048207mol

Explanation:

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Assuming you start with 10.0 g of zinc and 10.0 g hydrochloric acid, identify the limiting reagent and determine what mass of th
Liula [17]
The balanced chemical reaction for the substances given would be as follows:

Zn + 2HCl = ZnCl2 + H2

We are given the amounts of the reactants used in the reaction. We use these amounts to determine which is the limiting and excess reactant. We do as follows:

10 g Zn (1 mol / 65.38 g) = 0.1530 mol
10 g HCl (1 mol / 36.46 g) =  0.2743 mol

From the the stoichiometric ratio which is 1 is to 2, the limiting reactant would be hydrochloric acid and the excess would be zinc metal.

Mass of zinc that remains = 0.1530 - (0.2743 / 2) = 0.0159 g Zn 
5 0
3 years ago
8. (16 pts.) Using sentences, compare a dipeptide to a fatty acids specifically in terms of water
rosijanka [135]

Answer: It's not good to make a bomb out of cleaning supplies please don't do it unless your in a Meth Lab

Explanation:

6 0
3 years ago
The quantity of heat required to change the temperature of 1 g of a substance by 1⁰c is defined as
Alex
Specific heat is the quantity of heat required to change the temperature of 1 gram of a substance by 1 degree Celsius. It is the amount per unit mass that is required to raise the temperature by one degree Celsius. Every substance has its own specific heat and each has its own distinct value. The units of specific heat are joules per gram-degree Celsius (J/f C) and sometimes J/Kg K may also be used.
8 0
3 years ago
Determine the formula weight of BeCl₂.
tia_tia [17]
Be= Beryllium= weight 9.01
Cl= Chlorine= weight 35.45
Since there are 2 Chlorine, you have to add Chlorine twice.
9.01 + 35.45 + 35.45= 79.91

Answer: 79.91
(This answer does not include sig.figs)
4 0
3 years ago
Why do group 1 cations form precipitates when mixed with hcl?
Xelga [282]
Both of you are overlooking a pretty big component of the question...the Group I cation isn't being dissociated into water. We're testing the solubility of the cation when mixed with HCl. And this IS a legitimate question, seeing as our lab manual is the one asking. 

<span>By the way, the answer you're looking for is "Because Group I cations have insoluble chlorides". </span>

<span>"In order...to distinguish cation Group I, one adds HCl to a sample. If a Group I cation is present in the sample, a precipitate will form." </span>
8 0
3 years ago
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