3 years ago

How many moles are in 25.90 grams of NaCl

Chemistry

1 answer:

inessss [21]3 years ago

7 0

Answer:

0.44316859040048207mol

Explanation:

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3 years ago

A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?

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Answer: $1.67\times 10^{-3}$

Explanation:

$ClCH_2COOH\rightarrow ClCH_2COO^-+H^+$

cM 0 0

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So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Given: c = 0.15 M

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$K_a$ = ?

Putting in the values we get:

Also $pH=-log[H^+]$

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Thus the vale of $K_a$ for the acid is $1.67\times 10^{-3}$

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