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Tju [1.3M]
2 years ago
15

Place the following in order of increasing molar entropy at 298 K.

Chemistry
1 answer:
Genrish500 [490]2 years ago
3 0

Answer:

SO < CO2 < C3H8

Explanation:

Entropy refers to the degree of disorderliness of a system. The standard molar entropy of a substance refers to the entropy of 1 mole of the substance vunder standard conditions.

The molar entropy depends on the number of microstates in the system which in turn depends on the number of atoms in the molecule.

C3H8 has 11 atoms and hence the highest number of microstates followed by CO2 having three atoms and least of all SO having only two atoms.

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Hope I've helped. 

            - Dotz
6 0
3 years ago
From standard reduction potentials, calculate the equilibrium constant at 25 ∘c for the reaction 2mno−4(aq)+10cl−(aq)+16h+(aq)→2
garik1379 [7]

Answer:

\boxed{\text{57.9}}

Explanation:

Step 1. Determine the cell potential

                                                                                 <u>     </u><u>E°/V</u><u>      </u>

2MnO₄⁻ + 16H⁺ + 10e⁻ → 2Mn²⁺+ 8H₂O                      1.507

<u>10Cl⁻ ⟶ 5Cl₂ + 10e⁻                                             </u>     <u>-1.358 27 </u>

2MnO₄⁻ + 10Cl⁻ + 16H⁺⟶ 2Mn²⁺ + 5Cl₂ + 8H₂O      0.149

Step 2. Calculate K

The formula relating K and E is

E = \dfrac{RT}{nF} \ln K

E = 0.149 V

R = 8.314 J·K⁻¹mol⁻¹

T = 25 °C = 298.15 K

n = 10

F = 96 485 C/mol

0.149 = \dfrac{8.314 \times 298.15}{10\times 96 485} \ln K\\\\0.149 = 0.002 570 \ln K\\\\\ln K = \dfrac{0.149}{0.002570} = \textbf{57.9}

The value of the equilibrium constant is \boxed{\textbf{57.9}}

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Brilliant_brown [7]

Answer:

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Explanation:

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