Her sample space is also the list of local businesses.
Sampling is a technique used in statistics when researchers choose a representative subset of a larger population and utilize that subset to carry out a study. Probability sampling and non-probability sampling are the two main types of sampling. Selecting the group from whom you will actually gather data for your study is the process of sampling. If you wanted to examine the perspectives of students at your university, for instance, you could interview a sample of 100 students. With the help of sampling, you can test a statistical hypothesis on the features of a population.
The yellow pages are used by the researcher to do research on neighborhood companies. As a result, her sample space also includes a list of nearby companies.
Complete question: A researcher is conducting a study on local businesses. In order to create her sample, she uses the Yellowpages and a dice. She rolls the dice, and, depending on the number rolled, counts that many businesses down in the list to call. What is her sampling frame?
The list of local businesses in the Yellowpages.
All businesses within a 
radius.
The list of local businesses in the newspaper.
All businesses in the state she is located in.
The list of registered businesses in her area.
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There are extra periods so I’m not exactly sure but I think it’s 00.96
T. T tt T. T t. T t. T. T. T. T ttt t t. T. T. Tt. Got. T. T. Tt. Try. T. T tt. Tt. T. T. T. T. T. T. Tt. T. T. T. T. T. T t. Tt. T. T. T. T. Tt. T. T. T. T. T. T t. T. T. T. T. T. T t. Tt. T. T t. T. T. T. T. T. T. T. T. T t
Answer:
y = -6/5x + 1
Step-by-step explanation:
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)
