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Rzqust [24]
3 years ago
13

A severe thunderstorm, known as a supercell, forms. It begins in an area where cold, dry, polar air meets warm, moist, tropical

air, and the atmosphere is unstable. The wind coming into this storm begins to swirl, creating a swirling area of very low pressure. Which of the following is likely to occur in these conditions? A. hurricane B. lightning C. tornado D. cold front
Physics
2 answers:
alexdok [17]3 years ago
8 0

Answer:

A tornado can, surprisingly, cause a supercell, so the answer would be C.) tornado

Explanation:

When cold, dry, and polar air meet warm, moist tropical air, the atmosphere becomes unstable causing a supercell.

Final Answer:

C.) tornado

Afterthought:

<em>Please give BRAINLEST!</em>

Thanks,

-johannelbekian

kirza4 [7]3 years ago
4 0

Answer:

The correct answer would be c! :D

Explanation:

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prohojiy [21]
  • Mass=m=1kg
  • Height=h=2cm=0.02m
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\\ \tt\hookrightarrow P.E=mgh

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\\ \tt\hookrightarrow PE=0.2J

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Q3. A man walks with a speed of 8 m/sec in 40 sec. How much distance was covered?
chubhunter [2.5K]

Answer:

it is320 m.

Explanation:

by formula

d= m/s×t

d= 8× 40

d=320 m

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How do you solve for frequency?
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5 0
3 years ago
A 5.75 mm high firefly sits on the axis of, and 11.3 cm in front of, the thin lens A, whose focal length is 5.77 cm . Behind len
weeeeeb [17]

Answer

given,

focal length of lens A = 5.77 cm

focal length of lens B= 27.9 cm

flies distance from mirror = 11.3 m

now,

Using lens formula

\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q}

\dfrac{1}{5.77} = \dfrac{1}{11.3} + \dfrac{1}{q}

q =11.79 cm

image of lens A is object of lens B

distance of lens = 59.9 - 11.79 = 48.11

now, Again applying lens formula

\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q'}

\dfrac{1}{27.9} = \dfrac{1}{48.11} + \dfrac{1}{q'}

q' =66.41 cm

hence, the image distance from the second lens is equal to q' =66.41 cm

6 0
3 years ago
An ideal refrigerator does 130. 0 j of work to remove 780. 0 j of heat from its cold compartment during each cycle. what is the
zheka24 [161]

The refrigerator's coefficient of performance is 6.

The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.

As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.

The heat produced in the cold compartment, H = 780.0 J

Work done in ideal refrigerator, W = 130.0 J

Refrigerator's coefficient of performance = H/W

                                                                     = 780/130

                                                                     = 6

Therefore, the refrigerator's coefficient of performance is 6.

Energy conservation requires the exhaust heat to be = 780 + 130

                                                                                          = 910 J

Learn more about  coefficient here:

brainly.com/question/18915846

#SPJ4

5 0
2 years ago
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