During an experiment, an object is placed on a disk that rotates about an axle through its center, as shown in Figure 1. The dis
1 answer:
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Answer:
a) 12.74 V
b) Two pairs of diode will work only half of the cycle
c) 8.11 V
d) 8.11 mA
Explanation:
The voltage after the transformer is relationated with the transformer relationshinp:
the peak voltage before the bridge rectifier is given by:
The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:
As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.
The averague voltage on a full wave rectifier is given by:
Using Ohm's law:
Answer:
Average velocity = 1.69 m/s
Average speed = 5.09 m/s
Explanation:
Given that
Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.
As we know that
Average velocity = Displacement / Total time
Average speed = Total distance / Total time
Average velocity:
Average velocity = Displacement / Total time
Total displacement = 37 - 18.5 = 18.5 m
Total time = 9.1 + 1.8 =10.9 s
Average velocity = Displacement / Total time
Average velocity = 18.5 / 10.9
Average velocity = 1.69 m/s
Average speed:
Average speed = Total distance/ Total time
Total distance = 37 + 18.5 = 55.5 m
Total time = 9.1 + 1.8 =10.9 s
Average speed = Total distance/ Total time
Average speed = 55.5 / 10.9
Average speed = 5.09 m/s
Answer: The velocity at different marked time points are given as
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
Explanation:
The slope of the tangent of the curve indicates the instantaneous velocity. So if the slope of the tangent is positive, that Is, the tangent makes a positive angle (above the horizontal axis) with the horizontal
axis, then the velocity at this point is positive, and if the slope of the tangent is negative, that is the tangent makes a negative angle with the horizontal axis (below the horizontal axis), then the velocity at this point is negative.
When the tangent of the line is parallel to the horizontal axis, the velocity is 0.
From the position-time graph attached, the sign on the instantaneous velocity for each time marked on the graph is given below
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
QED!
