Let the number<span> be H T O. Ones digit = O Given that. O =10−5 ⇒ O =5. Also is given that tens digit T is 2 </span>more than<span> ones digit O ⇒ tens digit T = O +2=5+2=7. ∴ The </span>number<span> is. H 75. Given also is that "</span>number<span> is </span>less<span> than </span>200<span> and </span>greater than 100<span> " ⇒ H can take value only =1. We get our </span>number<span>as 175.</span>
Starting with 113+ (2x+5)=180, combine like terms and to get 118+2x=180. Subtract 180-118, which gives you 62. Then you have 2x=62. Divide both sides by 2 to get a final answer of x=31.
<h2>1st Equation:</h2>
Answer for A:
Answer for B:
<h2>2nd Equation:</h2>
Answer:
<u>hope it helps</u><u>.</u>
F(x) = 2x - 4
f(2 ≤ x) = 2(2 ≤ x) - 4
f(x ≥ 2) = 2(x ≥ 2) - 4
f(x ≥ 2) = 2(x) ≥ 2(2) - 4
f(x ≥ 2) = 2x ≥ 4 - 4
f(x ≥ 2) = 2x ≥ 0
f(x ≥ 2) = x ≥ 0
f(x) = 2x - 4
f(x ≤ 6) = 2(x ≤ 6) - 4
f(x ≤ 6) = 2(x) ≤ 2(6) - 4
f(x ≤ 6) = 2x ≤ 12 - 4
f(x ≤ 6) = 2x ≤ 8
f(x ≤ 6) = x ≤ 4
