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3 years ago

Which is an example of the force of attraction between two objects that have mass?

Physics

2 answers:

djverab [1.8K]3 years ago

6 0

Magnetism or gravity

Genrish500 [490]3 years ago

3 0

According to multiple scientific experiments, most objects develop an attraction towards Candice.

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The dogs of four-time Iditarod Trail Sled Dog Race champion Jeff King pull two 100-kg sleds that are connected by a rope. The sl

azamat

Answer:

Part a)

$a = 2.4 m/s^2$

Part b)

$F = 120 N$

Explanation:

Two sleds are connected by a rope

mass of each sled is given as

$m = 100 kg$

now we know that dog exert pulling force on the rope connected to first sled

$F = 240 N$

Part a)

By newton's first law we know that

$F = (m + m)a$

$240 = (100 + 100)a$

$a = \frac{240}{100}$

$a = 2.4 m/s^2$

Part b)

As we know that force between two ropes will pull the sled behind

so we will have

$F = ma$

$F = 100(1.20)$

$F = 120 N$

7 0

3 years ago

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Which properties do metalloids share with metals?

IgorC [24]

Share electrons, have electrical conductivity and have thermal conductivity

4 0

3 years ago

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the minimum flying speee for a bird called a house martin is 9.0ms^-1. it reaches this speed by falling from its nest before swo

Lilit [14]

Answer:

The nest must be about 4.15 meters above ground

Explanation:

Use the velocity equation under accelerated motion (acceleration of gravity ):

$v_f=v_i+a\,*\,t$

which for this case has initial velocity = 0 (falls from the nest), final velocity = 9 m/s, and a = 9.8 m/s^2, then we can find the time needed in air while falling to reach the required speed:

$v_f=v_i+a\,*\,t\\9=0+9.8\,t\\t=\frac{9}{9.8} \, sec\\t \approx 0.92\,\, sec$

We now use this time value to find the distance covered in free fall during 0.92 seconds:

$d=\frac{1}{2} \,9.8 \,t^2=4.9\,(0.92)^2=4.147 \,meters\approx 4.15\,meters$

8 0

3 years ago

Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has

k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0

3 years ago

What parts of an atom determines which element it is?

uysha [10]

Explanation:

The protons determines the atomic number which helps in identifying an atom of an element

4 0

4 years ago

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