Describe what physical meaning is attributed to ψ 2

1 answer:

6 0

In quantum mechanics, $\psi^2$ the basic wave function has no physical meaning or significance. However, $|\psi|^2$ represents the probability distribution of particle in a given space.

Probability $\propto$ $|\psi|^2$

So when you will put a position and a time in $\psi^2$ function, it will give you the probability of finding the particle at that particular position and at the given time.

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the cyclist has a mass of 50kg and is acceleratiing at 0.9m/s^2. What is the size of the unbalanced force F acting on the cyclis

stiv31 [10]

Answer:

45 N

Explanation:

The question can be solved by using Newton's second law:

F = ma

where

F is the net (unbalanced) force on the cyclist

m is the mass of the cyclist

a is his acceleration

In this problem:

m = 50 kg

$a=0.9 m/s^2$

Therefore, the unbalanced force is

$F=(50)(0.9)=45 N$

4 0

4 years ago

What does it mean to say that the forces acting on an object are balanced?

yan [13]

Hello,

Your correct answer would be A. "The forces occur as pairs of forces with equal magnitude and direction."

Sources: Google.

Hope this helps!

~Hotttwizzlers

5 0

3 years ago

Find the magnitude of a fourth force on the stone that will make the vector sum of the four forces zero.

Tanya [424]

100cos30° + 80cos120° + 40cos233° + Dx = 0
Dx = -22.53 N 

y components: 
100sin30° + 80sin120° + 40sin233° + Dy = 0 
Dy = -87.34 N 

magnitude of D: 
sqrt[(-22.53)² + (-87.34)²] 
90.2 N 

direction of D: 
arctan[(-87.34)/(-22.53)] 
75.5° ref, but since Dx and Dy are both negative, we know this vector is in QIV: 
360 - 75.5° = 284.5°

7 0

3 years ago

What is the model size to actual size

Murljashka [212]

Answer:

You have to divide your real measurement to the model. For example, if your real measurement is 5m and your model is 20cm, divide 5/20 =1/4 and that means the ratio would be 1:4.

Explanation:

7 0

3 years ago

On the same spring day, a station near the equator has a surface temperature of 25°C, 15°C higher than the middle-latitude city

DedPeter [7]

Answer:

The air temperature at the tropopause is - 79 °C

Explanation:

We know that a station near the equator has a surface temperature of 25°C

Vertical soundings reveal an environmental lapse rate of 6.5 °C per kilometer.

The tropopause is encountered at 16 km.

In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.