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Arlecino [84]
3 years ago
9

Which properties do metalloids share with metals?

Physics
2 answers:
IgorC [24]3 years ago
4 0
Share electrons, have electrical conductivity and have thermal conductivity
Marina CMI [18]3 years ago
4 0

Answer:

The properties metalloids shares with metals are as follows ;

Metalloids like germanium and silicon conduct electricity under special condition .

Metalloids  can form alloys just like metals.

Metalloids like germanium, arsenic and  antimony are lustrous metallic looking solid.  

Explanation:

Metalloids are intermediate elements between metals and non metals. This element sometimes act like metal and other time act like non metals. Metals are good conductor of heat and electricity, lustrous, malleable, ductile and form cations by donating electron(s) while non metal do not conduct heat or electricity  and are mostly anions. Metalloids have characteristics of both non metals and metals.

The properties metalloids shares with metals are as follows ;

Metalloids like germanium and silicon conduct electricity under special condition .

Metalloids  can form alloys just like metals

Metalloids like germanium, arsenic and  antimony are lustrous metallic looking solid.  

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A ball is rolling along at speed v without slipping on a horizontal surface when it comes to a hill that rises at a constant ang
MissTica

Answer:

The ball has an initial linear kinetic energy and initial rotational kinetic energy which can both be converted into gravitational potential energy. Therefore the hill with friction will let the ball reach higher.

Explanation:

The ball has an initial linear kinetic energy and initial rotational kinetic energy which can both be converted into gravitational potential energy. Therefore the hill with friction will let the ball reach higher.

This is because:

If we consider the ball initially at rest on a frictionless surface and a force is exerted through the centre of mass of the ball, it will slide across the surface with no rotation, and thus, there will only be translational motion.

Now, if there is friction and force is again applied to the stationary ball, the frictional force will act in the opposite direction to the force but at the edge of the ball that rests on the ground. This friction generates a torque on the ball which starts the rotation.

Therefore, static friction is infact necessary for a ball to begin rolling.

Now, from the top of the ball, it will move at a speed 2v, while the centre of mass of the ball will move at a speed v and lastly, the bottom edge of the ball will instantaneously be at rest. So as the edge touching the ground is stationary, it experiences no friction.

So friction is necessary for a ball to start rolling but once the rolling condition has been met the ball experiences no friction.

6 0
3 years ago
Are cells made of tisse?
zepelin [54]

Answer:

Yes

Explanation:

Cells make up tissues. Hope this helped

5 0
3 years ago
Read 2 more answers
A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
Sonja [21]

The time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine time interval during which the proton is in the field.

<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ



According to the question, we have -

Entering Velocity (v) = 20 i  m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j  m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

d = $\frac{2\pi r}{4} = $\frac{\pi R}{2}

Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

t = $\frac{\pi R}{2v} = \frac{\pi R}{40}

Hence, the time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}

To solve more questions on Force on charged particle, visit the link below-

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6 0
2 years ago
when the particles of the medium move back and forth along the direction of the wave motion, the wave is a
Bezzdna [24]

Transverse waves are always characterized by particle motion being perpendicular to wave motion. A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.

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3 years ago
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<span>An ecosystem can only sustain so many organisms. That limit would be its carrying capacity. If the population goes above that number then other factors will cause the population to crash and then rebound to a constant level. </span>
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3 years ago
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