Pls help me asap... plssss..... ty

Mathematics

1 answer:

olasank [31]3 years ago

5 0

Answer:

Well... "Alphabets" in math, are defined as variables...

And we use variables to show the things that we are multiplying, dividing, subtracting, or adding. Like: Beach balls=B "Tommy has to blow up 20 beach balls before he can go to the beach, his mom offers to help him. How many beach balls do each of them have to blow up?" One equation we could use is "B/2 or B divided by 2" :)

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B1%7D%20" id="TexFormula1" title=" \sqrt{1} " alt=" \sqrt{1} " align="absmiddle" c

bazaltina [42]

The answer will be 1

5 0

4 years ago

From Euler’s relation eiθ = cosθ + isinθ,

adelina 88 [10]

Answer:

(a) The graphic representation is in the attached figure.

(b) $\cos(\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$ .

(c) $\sin(\theta) = \frac{e^{i\theta} - e^{-i\theta}}{2i}$ .

Step-by-step explanation:

(a) Given a complex number $e^{i\theta}$ we know, from Euler's formula that $e^{i\theta} = \cos(\theta)+i\sin(\theta)$ . So, it is not difficult to notice that

$|e^{i\theta}|^2 = \cos^2(\theta)+\sin^2(\theta) =1$

so it is on the unit circumference. Also, notice that the Cartesian representation of the complex number is $(\cos(\theta), \sin(\theta))$ .

Now,

$e^{-i\theta} = \cos(\theta)+i\sin(-\theta) = \cos(\theta)-i\sin(\theta)$ .

Notice that $e^{-i\theta}$ has the same modulus that $e^{i\theta}$ , so it is on the unit circumference. Beside, its Cartesian representation is $(\cos(\theta), -\sin(\theta))$ .

So, the points $(\cos(\theta), \sin(\theta))$ and $(\cos(\theta), -\sin(\theta))$ are symmetric with respect to the X-axis. All this can be checked in the attached figure.