<u>Answer:</u>
2400 mL
<u>Explanation:</u>

According to this equation, the stoichiometric ratio between
and
for the complete reaction is 1:2.
We know that the number of moles of
can be calculated using the mole formula. (<em>number of moles = mass / molar mass</em>)
Moles of Calcium =
= 1.5 mol
So the moles of
=
= 3.0 mol
<em>Volume of HCl solution = Moles of HCl/ concentration of HCl</em>
Volume of HCl solution =
= 2400 mL
Answer:The formula for the compound formed between sodium and oxygen will be Na2O; a ratio of 2 Na atoms for each O atom.
Explanation:
During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.
<h3>What is electrolysis?</h3>
Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them. In this process, the atoms and ions are interchanged by the addition or removal of electrons.
The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.
During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.
At anode : 2 Cl⁻ → Cl₂ + 2e⁻
At cathode: 2 Li⁺ + 2e⁻ → Li
Learn more about electrolysis, here:
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Because it relates to more than one branch of knowledge. It combines more than one academic disiplines.
Answer:
116.5 g of SO₂ are formed
Explanation:
The reaction is:
S₈(g) + 8O₂(g) → 8SO₂ (g)
Let's identify the moles of sulfur vapor, by the Ideal Gases Law
We convert the 921.4°C to Absolute T° → 921.4°C + 273 = 1194.4 K
5.87 atm . 3.8L = n . 0.082 L.atm/mol.K . 1194.4K
(5.87 atm . 3.8L) / (0.082 L.atm/mol.K . 1194.4K) = n → 0.228 moles of S₈
Ratio is 1:8, 1 mol of sulfur vapor can produce 8 moles of dioxide
Then, 0.228 moles of S₈ must produce (0.228 . 8) /1 = 1.82 moles
We convert the moles to g → 1.82 moles . 64.06 g /1mol = 116.5 g