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laila [671]
3 years ago
9

a beaker of benzene is at room temperature. what is its vapor pressure. Is this vapor pressure large enough to cause the benzene

to boil at sea level answers
Chemistry
1 answer:
Serhud [2]3 years ago
8 0

Answer:

(1). The vapor pressure is 91 mmHg at 20°C.

(2). No, benzene will not boil at sea level.

Explanation:

Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.

The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.

Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.

The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).

71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.

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Read 2 more answers
HELP PLEASE!!!
hjlf

Answer:

1. 22 moles of FeCr2O7

2. 53.95 moles of O2

3. 77.25 moles of O2

Explanation:

4 FeCr2O7+ 8 K2CO3 + 1 O2-----------> 2 Fe2O3+ 8 K2CrO4 + 8 CO2

1. How many moles of FeCr2O7 are required to produce 44 moles of CO2?

Equate the moles of the compounds in the question

4 moles of FeCr2O7 produces 8 moles of CO2

(44 *4 / 8) moles of FeCr2O7 will produce 44 moles of CO2

= 44 *4 / 8

= 22 moles

2. How many moles of 02 is required to produce 107.9 moles of Fe2O3?

1 mole of O2 = 2 moles of Fe2O3

(107.9 *1 / 2) moles of O2 will be required to produce 107.9 moles of Fe2O3

= 107.9 * 1 / 2

= 53.95 moles

3. The ratio of moles for FeCr2O7 to O2 in the reaction is

4 : 1

309 : x ; solve for x

x = 309 * 1 / 4

x =77.25 moles of O2

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3 years ago
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