Need help on this circuit question

A ball is thrown up at 30m/s from the ground. What is it s maximum height? How long did it take?

Rzqust [24]

Answer:

Maximum height reached by the ball thrown up at 30m/s is 3.06 seconds and the height reached is 45.9 meters

Explanation:

Given:

Initial velocity $u=30 \mathrm{m} / \mathrm{s}$

To find :

maximum height =?

time taken=?

Solution:

Step 1:Finding the time taken to reach the highest point:

The velocity of the ball at its highest ,final velocity v=0

Using the formula,

$v=u+a t$

Where a is acceleration due to gravity.Its value is $-9.8 m / s^{2}$

Substituting the values:

$0=30+(-9.8) t$

$-30=(-9.8) t$

$t=\frac{30}{9.8}$

$t=3.06 \mathrm{seconds}$

Step 2: finding the highest point

Using the formula

$v^{2}-u^{2}=2 a s$

where

s is the maximum highest.

Substituting values

$0^{2}-(30)^{2}=2(-9.8) s$

$0-900=(-19.6) s$

$-900=(-19.6) s$

$s=\frac{900}{19.6}$

$s=45.9 \text { meters }$

Result:

Thus the maximum height reached is 45.9 meters in 3.06 seconds

3 0

3 years ago

Read 2 more answers

5. A 5.0 kg object accelerates uniformly from rest for 5.0 s and reaches a final velocity of 20.0 m/s. At 3.0 s, what is the obj

irina [24]

Answer:

jack JACKKK

Explanation:

OK YAHHHHH SO DO THIS

3 0

4 years ago

The energy needed to change an amount of a substance from a solid to a liquid is the

Korvikt [17]

Answer:

Heat or thermal energy!!!

Explanation: When heat is added the particles speed up at rapid rates causing the state of the object to change nd in order to melt it must be heated.

3 0

4 years ago

El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es

topjm [15]

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

P₁ = P₂

pressure is defined by

P = F / A

we subtitute

F₁ / A₁ = F₂ / A₂

F₁ = F₂ A₁ / A₂

the area in a circle is

A = π r² = π d² / 4

we substitute

F₁ = F₂ (d₁ / d₂)²

we calculate

F₁ = 17640 (2/32)²

F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

P₁ = F₁ / A₁

P₁ = F₁ 4 / π d₁²

let's calculate

P₁ = 68.9 4 / (π 0.02²)

P₁ = 219.3 Pa

3 0

3 years ago

You've always wondered about the acceleration of the elevators in the 101-story-tall Empire State Building. One day, while visit

kondor19780726 [428]

Answer:

(i) The maximum acceleration upward is 2.02 m/s².

(ii) The maximum acceleration downward is 1.39 m/s².

Explanation:

Let a be the maximum acceleration of the elevator.

The mass of the person at ground is 150 lb. We have to convert the mass into kg,

1 lb = 0.453592 kg

150 lb = 68 kg

170 lb = 77 kg

120 lb = 54 kg

(i) The person experience a force due to Earth's gravity in the downwards direction. The magnitude of this force is:

F₁ = mg = 68 x 9.8 = 666.4 N

The weight of the person decreases as the elevator is moving upwards. So, the force experienced by the person in this case due to gravity is:

F₂ = 54 x 9.8 = 529.2 N

Applying Newton's force equation;

(F₁ - F₂) = ma

(666.4 - 529.2) = 68 x a

a = 2.02 m/s²

(ii) The weight of the person increases as the elevator is moving downwards. So, the force experienced by the person in this case due to gravity is:

F₂ = 77 x 9.8 = 754.6 N

Applying Newton's force equation;

(F₁ - F₂) = ma

(666.4 - 754.6) = 68 x a

a = -1.30 m/s²

8 0

4 years ago