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kirill [66]
3 years ago
11

A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial

, the student uses a different amount of sugar and a different temperature of water.
What is wrong with this experimental design?
A. The student does not have a dependent variable.
B. The student changed too many variables.
C. The student needs to perform more trials.
D. The student did not change enough variables.
Physics
1 answer:
Sveta_85 [38]3 years ago
7 0
B- the student changed too many variables
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A charge of 1. 5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How
ELEN [110]

It is a type capacitor is in which two metal plates arranged in such a way so that they are connected in parallel . The potential energy is stored in the capacitor will be 2.7×10⁻⁵.

<h3>What is parallel plate capacitor ?</h3>

It is an type capacitor is an in which two metal plates arranged in such a way so that they are connected in parallel and have some distance between them.

A dielectric medium is a must in between these plates. helps to stop the flow of electric current through it due to its non-conductive nature .

The given data in the problem is;

Q is the charge= 1.5 µC

V is the change in voltage across the plates is = 36 V.

U is the potential energy=?

The formula for the potential energy is given by;

\rm U= \frac{1}{2} \times Q \times V \\\\ \rm U= \frac{1}{2} \times 1.5\times 10^{-6} \times 36 \\\\  \rm U=2.7\times10^{-5}

Hence the potential energy is stored in the capacitor will be 2.7×10⁻⁵.

To learn more about the parallel plate capacitor refer to the link;

brainly.com/question/12883102

3 0
2 years ago
cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your
sp2606 [1]

We have that the time in seconds, minutes, and hours is

t=1.083*10^{-4}s

T_{min}=1.805*10^{-6}min

T_{hours}=3.0083*10^{-8}hours

From the Question we are told that

Velocity v=13.0m/s

Distance d=120 km

Generally the equation for the Time  is mathematically given as

t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s

Therefore

T_{min}=1.083*10^{-4}s/60

T_{min}=1.805*10^{-6}min

And

T_{hours}=T_{min}/60

T_{hours}=3.0083*10^{-8}hours

For more information on this visit

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4 0
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How many normal modes of oscillation or natural frequencies does each if the following have: (
Vadim26 [7]
<span>Each of these systems has exactly one degree of freedom and hence only one natural frequency obtained by solving the differential equation describing the respective motions. For the case of the simple pendulum of length L the governing differential equation is d^2x/dt^2 = - gx/L with the natural frequency f = 1/(2π) √(g/L). For the mass-spring system the governing differential equation is m d^2x/dt^2 = - kx (k is the spring constant) with the natural frequency ω = √(k/m). Note that the normal modes are also called resonant modes; the Wikipedia article below solves the problem for a system of two masses and two springs to obtain two normal modes of oscillation.</span>
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What kind of light would be the best to use to look inside a cold dark cloud and see the warm stars forming inside?
lys-0071 [83]
<h2>Answer: Infrared light</h2>

A dark nebula is a cloud of dust and cold gas, which does not emit visible light and hides the stars it contains.

These types of nebulae are composed mainly of the hydrogen they obtain from nearby stars, which is their fuel.

It is using infrared light that we can "observe" and analyze in detail what happens in the inner parts of these nebulae.

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All isotopes of a particular element have the same atomic number. How then do the isotopes of a particular element differ?
xz_007 [3.2K]
Isotopes of an element will contain the same number of protons and electrons but will differ in the number of neutrons they contain. In other words, isotopes have the same atomic number because they are the same element but have a different atomic mass because they contain a different number of neutrons
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