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kirill [66]
2 years ago
11

A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial

, the student uses a different amount of sugar and a different temperature of water.
What is wrong with this experimental design?
A. The student does not have a dependent variable.
B. The student changed too many variables.
C. The student needs to perform more trials.
D. The student did not change enough variables.
Physics
1 answer:
Sveta_85 [38]2 years ago
7 0
B- the student changed too many variables
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A pendulum is transported from sea-level, where the acceleration due to gravity g is 9.80 m/s2, to the bottom of Death Valley. A
tatyana61 [14]

Answer: the value of g in Death Valley is 10.417 m/s²

Explanation:

Given that;

acceleration due to gravity at the point is g = 9.8 m/s²

Lets say the acceleration due to gravity at the bottom of Death valley is g'

as the period of the pendulum is decreased by 3.00%

T' = 0.97 T  

T is the period of the pendulum at sea level  and T' is the period of the pendulum at bottom of Death valley

therefore from the relation

T = 2π√(l/g)

g'/g = T²/T'²

g' = (T²/ (0.97T)²)g

g' = 1.063g

g' = 10.417 m/s²

therefore the value of g in Death Valley is 10.417 m/s²

7 0
3 years ago
At each corner of a square of side l there are point charges of magnitude Q, 2Q, 3Q, and 4Q.What is the magnitude and direction
bogdanovich [222]

Answer:

magnitude of force on charge 2Q  = \frac{KQ^{2} }{I^{2} }

Direction of force on charge = 61 ⁰

Explanation:

The magnitude on the force on the charge can be evaluated by finding the net force acting on the charge 2Q  i.e x-component of the net force and the y-component of the net force

║F║ = \sqrt{f_{x}^{2} + f_{y}^{2}    }  =  after considering the forces coming from Q, 3Q and 4Q AND APPLYING COULOMBS LAW

magnitude of force acting on 2Q = \frac{KQ^{2} }{I^{2} }

The direction of the force on charge 2Q is calculated as

tan ∅ = \frac{f_{y} }{f_{x} } = 1.8284

therefore ∅ = tan^{-1}  1.8284

= 61⁰

3 0
3 years ago
A car drives at a velocity of 6.8 m/s for 250 seconds. How far did it travel?
Leno4ka [110]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

As we know, Displacement =

\qquad \sf  \dashrightarrow \: velocity  \times time

\qquad \sf  \dashrightarrow \: 6.8 \times 250

\qquad \sf  \dashrightarrow \: 1700 \: m

<h3>OR </h3>

\qquad \sf  \dashrightarrow \: 1.7 \: km

The car travelled 1700 meters ( 1.7 km )

8 0
2 years ago
explain how a maglev train provides evidence that magnetic fields can apply forces between objects that do not touch.
Furkat [3]

Answer:

Powerful electromagnets are fitted on top of guideways either ttract or repel the magents fitted on the bottom of train. The froce of attraction/repulsion rasies the train in hovering position.

Explanation:

Magentic fields exist between two opposite/like poles. The poles do not have to be touching each other. They can be separated by a distance in a medium that doesn' block magnetic field.

In magelv train the magnetic forces between two poles are used to operate the train. The two poles are separated by train body and air.

4 0
2 years ago
Pleaseeeeeee answer :3!
Ludmilka [50]

Work = (force) x (distance)

Work = (21 Newtons) x (9 meters) = 189 Joules

Power = (work done) / (time to do the work)

Power = (189 Joules) / (3 sec)

Power = (63 watts/sec)

Power = 63 watts (D)

3 0
3 years ago
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