The answer is the second one
If you want a fast explanation
You have to remember that the minus sign indicates which direction the hyperbole will follow, if the minus is on x, that indicates the hyperbole will be vertical, and if the minus is in y, then it'll be horizontal
If you check the vertices points those indicates the length of 2a thus thatll be 6
To get the center just use middle point equation and you'll get (1,3)
Just to know, a indicates the distance from the center to the vertices, b indicates how wide the hyperbole box is, and c indicates the distance from center to focis
A=3
B=?
C=6
We use Pythagoras so
![b = \sqrt{(6) ^{2} - (3) ^{2} }](https://tex.z-dn.net/?f=b%20%3D%20%20%5Csqrt%7B%286%29%20%5E%7B2%7D%20%20-%20%283%29%20%5E%7B2%7D%20%20%7D%20%20)
Thus you get
![b = \sqrt{27}](https://tex.z-dn.net/?f=b%20%3D%20%20%5Csqrt%7B27%7D%20)
With that data now you can get the equation
You know that below (y-3)^2 there should be a^2 so that means there will be the 9
And in the (x-1)^2 there should be b^2 so that means there will be the 27
PD. The 3 besides y, and 1 besides x represent the center
Answer:
<em>290.5 square miles</em>
Step-by-step explanation:
Consider splitting this figure into two mini rectangles and a triangle, each of given lengths;
![Dimensions of Rectangle 1 - Height ; 5 mi, Length ; 7 mi,\\Area of Rectangle 1 - Height * Length = 5 mi * 7 mi = 35 mi^2\\\\Dimensions of Rectangle 2 - Height ; 18 mi, Length ; 8 mi,\\Area of Rectangle 2 - Height * Length = 23 mi * 8 mi = 184 mi^2\\\\Dimensions of Mini Right Triangle - Height ; 11 mi, Base ; 8 + 5 = 13 mi,\\Area of Mini Right Triangle - 1 / 2 * Base * Height = 1 / 2 * 13 mi * 11 mi = 71.5 mi^2,\\\\Area of Figure = 35 mi^2 + 184 mi^2 + 71.5 mi^2 = 290.5 square miles](https://tex.z-dn.net/?f=Dimensions%20of%20Rectangle%201%20-%20Height%20%3B%205%20mi%2C%20Length%20%3B%207%20mi%2C%5C%5CArea%20of%20Rectangle%201%20-%20Height%20%2A%20Length%20%3D%205%20mi%20%2A%207%20mi%20%3D%2035%20mi%5E2%5C%5C%5C%5CDimensions%20of%20Rectangle%202%20-%20Height%20%3B%2018%20mi%2C%20Length%20%3B%208%20mi%2C%5C%5CArea%20of%20Rectangle%202%20-%20Height%20%2A%20Length%20%3D%2023%20mi%20%2A%208%20mi%20%3D%20184%20mi%5E2%5C%5C%5C%5CDimensions%20of%20Mini%20Right%20Triangle%20-%20Height%20%3B%2011%20mi%2C%20Base%20%3B%208%20%2B%205%20%3D%2013%20mi%2C%5C%5CArea%20of%20Mini%20Right%20Triangle%20-%201%20%2F%202%20%2A%20Base%20%2A%20Height%20%3D%201%20%2F%202%20%2A%2013%20mi%20%2A%2011%20mi%20%3D%2071.5%20mi%5E2%2C%5C%5C%5C%5CArea%20of%20Figure%20%3D%2035%20mi%5E2%20%2B%20184%20mi%5E2%20%2B%2071.5%20mi%5E2%20%3D%20290.5%20square%20miles)
<em>Solution; 290.5 square miles</em>
The minimum distance between the asteroid and the sun is 10 - 6 =4
The given hyperbolic path defined as
divide both the sides by 576,
The general equation of
hyperbola is written as
;
Compare with above mention equation
Here
The distance between the asteroid and the sun is seen by figure -1
or
⇒c =10
The minimum distance between the asteroid and the sun is 10 -6 =4
Answer: 60cm
Step-by-step explanation:
6 times 2 is 12
12 times 5 is 60
Perimeter is , or around 63.89 in.
If you meant that the area was 225 in²:
Perimeter is 60 in