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lina2011 [118]
3 years ago
13

A functin is defined by f(x) = 3x2 - x3. What is f(2)?

Mathematics
2 answers:
hammer [34]3 years ago
7 0

Answer:

12-2x

Step-by-step explanation:

1. Replace the x in the equation with 2. f(2) = 3(2)*2-x(2)

2. Simplify, multiply 3 by the 2 in parenthesis, then by the 2 next to it (this will give you 12 because 3*2*2 = 12) Then multiply the x with the 2 in the parentheses next to it. f(2) = 12-2x

This is the most you can simplify so your answer could probably be 12-2x.

grandymaker [24]3 years ago
4 0

Answer:

<u>6</u>

Step-by-step explanation:

When you say 3x2, I think you mean 3x^2. But I am not sure. So, we know that f(x)=3x^2-(2)3. And we have to find what f(2) is. So, we simply plug in the 2 in the equation.

f(2)=3(2)^2-(2)3

f(2)=2*3(2-1)

f(2)=2*3*1

f(2)=6

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Square root of 32 x square root of 1 over 18
lisov135 [29]
<h3>Solution:</h3>

\sqrt{32}  \times  \sqrt{ \frac{1}{18} }  \\  =  \sqrt{32}  \times  \frac{ \sqrt{1} }{ \sqrt{18} }  \\  =  \sqrt{32}  \times  \frac{1}{ \sqrt{18} }  \\  =  \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} }   \\  =  \frac{ \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2} }{ \sqrt{2 \times  {3}^{2} } }  \\  =  \frac{2 \times 2 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4}{3}

<h3>Answer:</h3>

\frac{4}{3}

<h3>Hope it helps...</h3>

ray4918 here to help

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3 years ago
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yawa3891 [41]
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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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