Answer:
a) 0.003512 moles
b) Moles C= 0.04214 moles carbon
Moles H = 0.07726 moles hydrogen
Moles O = 0.03863 moles of oxygen
c) C atoms = 2.54 *10^22 carbon atoms
H atoms = 4.65 *10^22 hydrogen atoms
O atoms = 2.33 *10^22 oxygen atom
Explanation:
Step 1: Data given
Mass of sucrose = 1.202 grams
Molar mass of sucrose = 342.3 g/mol
Step 2: Calculate moles of sucrose
Moles sucrose = Mass sucrose / molar mass sucrose
Moles sucrose = 1.202 grams / 342.3 g/mol
Moles sucrose = 0.003512 moles
Step 3: Calculate moles of each element
For 1 mol of C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen
Moles C: 12*0.003512 = 0.04214 moles carbon
Moles H: 22* 0.003512 = 0.07726 moles hydrogen
Moles O: 11* 0.003512 = 0.03863 moles of oxygen
Step 4: Calculate the number of atoms
C atoms = 6.022 *10^23 / mol * 0.04214 moles = 2.54 *10^22 atoms carbon
H atoms = 6.022 * 10^23 / mol * 0.07726 moles = 4.65 *10^22 atoms H
O atoms = 6.022 * 10^23 / mol * 0.03863 moles = 2.33 *10^22 atoms O
0.003512 moles of sucrose containse 6.022 *10^23 * 0.003512 = 2.11 * 10^21 sucrose molecules
