Answer:
52/27
Step-by-step explanation:
Answer:
y=12/5 (in decimal notation y=2.4)
Step-by-step explanation:
the value of 7y-2 = 10 more than 2y
7y-2 = 10+2y
7y-2y = 10+2
5y = 12
y = 12/5
y = 2.4
Answer:
c. 6.2 ± 2.626(0.21)
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 101 - 1 = 100
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.626
The confidence interval is:

In which
is the sample mean while M is the margin of error.
The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.
This means that 
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
Thus, the confidence interval is:

And the correct answer is given by option c.
Answer:
37 / 40 or 0. 925
Step-by-step explanation:
5/ 8 + 3 / 10
= 37 / 40
= 0. 925
Mark brainliest pls
Answer:
We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz
Step-by-step explanation:
Mean = 3.2 oz, sd = 0.13 oz
Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303
Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz
Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz