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myrzilka [38]
3 years ago
7

I NEED ANSWERS ASAP, TY:)​

Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0
J = 94x

example: 25 is your seconds so now you need to find the relationship to get to the 2,350. You could divide 2,350 and 25 and you would get the outcome of 94 .
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1 1/3 x 1 4/9 the product is
natka813 [3]

Answer:

52/27

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The value of 7y–2 is 10 more than the value of 2y
const2013 [10]

Answer:

y=12/5 (in decimal notation y=2.4)

Step-by-step explanation:

the value of 7y-2 = 10 more than 2y

7y-2 = 10+2y

7y-2y = 10+2

5y = 12

y = 12/5

y = 2.4

3 0
4 years ago
A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select
podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.626

The confidence interval is:

\overline{x} \pm M

In which \overline{x} is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that \overline{x} = 6.2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

\overline{x} \pm M = 6.2 \pm 2.626(0.21)

And the correct answer is given by option c.

5 0
3 years ago
Find the sum of 5/8 + 3/10 *
Gnom [1K]

Answer:

37 / 40 or 0. 925

Step-by-step explanation:

5/ 8 + 3 / 10

= 37 / 40

= 0. 925

Mark brainliest pls

5 0
3 years ago
The average weight of a medium size egg is found to be 3.2 oz, with a standard deviation of 0.13 oz. What is the heaviest egg (t
Over [174]

Answer:

We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz

Step-by-step explanation:

Mean = 3.2 oz, sd = 0.13 oz

Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303

Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz

Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz

3 0
3 years ago
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