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3 years ago

Write the explicit equation for -12,-1,10,21,32

Mathematics

1 answer:

Masteriza [31]3 years ago

4 0

Answer:

answer my question first please

Step-by-step explanation:

the answer

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1) y=-3x + 4 y = 3x - 2 (1,1)

puteri [66]

Answer:

y=3x-2

Step-by-step explanation:

your question didn't have any instructions so this might not be what you're looking for

set them equal to each other

-3x+4=3x-2

-3x-3x=-2-4

-6x=-6

x=1

plug in x=1

y=3(1)+4 =7

y=3(1)-2 =1

so, when x=1, y=1 in the expression y=3x-2

7 0

2 years ago

100-99+98-97+96-95+...+8-7+6-5+4-3+2-1

lina2011 [118]

$100-99+98-97+96-95+...+8-7+6-5+4-3+2-1\\\\=(100-99)+(98-97)+(96-95)+...+(4-3)+(2-1)\\\\=\underbrace{1+1+1+...+1}_{50}=\fbox{50}$

8 0

3 years ago

Read 2 more answers

Hii guys I need help with this I took a screenshot of it.

eduard

Answer:

x <= 9

Step-by-step explanation:

x -15 <= -6

+15. +15

x <=9

8 0

2 years ago

A surfboard is originally priced at $155. The online retailer gives a discount and the surfboard is now priced at $93. Enter the

GrogVix [38]

93 is 60 percent from the original price.
The discount reduces the original price by 40 percent.

7 0

3 years ago

What is the equation of the line perpendicular to Y-3x+1 that passes through the point (12,-6)?

erma4kov [3.2K]

Answer:

$3y + x = -6$

Step-by-step explanation:

Given

y = 3x + 1

Required

Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1

First, the slope of the line has to be calculated;

Th slope of a line is the coefficient of x in its linear equation;

This implies that the slope of y = 3x + 1 is 3

Having calculated the slope of the first line;

The relationship between both lines are perpendicularity; this implies that $m_1 * m_2 = -1$

Where m_1 = 3 and m_2 is the slope of the secodnd line

$m_1 * m_2 = -1$ becomes

$3 * m_2 = -1$

Divide both sides by 3

$\frac{3 *m_2}{m_2} = \frac{-1}{3}$

$m_2 = \frac{-1}{3}$

The equation of the line can be calculated using the folloing formula

$m = \frac{y - y_1}{x - x_1}$

Where $(x_1, y_1) = (12,-6)$ and $m_2 = \frac{-1}{3}$

The equation becomes

$\frac{-1}{3} = \frac{y -- 6}{x - 12}$

$\frac{-1}{3} = \frac{y + 6}{x - 12}$

Cross multiply

$-(x - 12)= 3(y + 6)$

$-x + 12=3y + 18$

Collect like terms

$12 - 18 = 3y +x$

$-6 = 3y + x$

$3y + x = -6$

4 0

2 years ago