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3 years ago

Does anyone know this?!

Physics

1 answer:

Valentin [98]3 years ago

8 0

Answer:

2 is the numerical answer.

Explanation:

Hello there!

In this case, according to the given information and formula, it is possible for us to remember that equation for the calculation of the average kinetic energy of a gas is:

$KE=\frac{3}{2} \frac{R}{N_A} T$

Whereas R is the universal gas constant, NA the Avogadro's number and T the temperature.

Which means that for the given ratio, we can obtain the value as follows:

$=\frac{\frac{3}{2} \frac{R}{N_A} T_1}{\frac{3}{2} \frac{R}{N_A} T_2} \\\\=\frac{T_1}{T_2} \\\\=\frac{500K}{250K} \\\\=2$

Regards!

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A ball thrown straight up climbs for 3.0 sec before falling. Neglecting air resistance, with what velocity was the ball thrown?

sesenic [268]

Answer:

Speed, u = 29.4 m/s

Explanation:

Given that, A ball thrown straight up climbs for 3.0 sec before falling, t = 3 s

Let u is speed with which the ball is thrown up. When the ball falls, v = 0

Using first equation of motion as :

v = u + at

Here, a = -g

So, u = g × t

$u=9.8\times 3$

u = 29.4 m/s

So, the speed with which the ball was thrown is 29.4 m/s. Hence, this is the required solution.

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4 years ago

What would the answer be ?

Marianna [84]

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3 years ago

A proton and an alpha particle (q = +2e, m = 4 u) are fired directly toward each other from far away, each with an initial speed

stich3 [128]

Answer:

Distance of closest approach, $r=1.91\times 10^{-14}\ m$

Explanation:

It is given that,

Charge on proton, $q_p=e$

Charge on alpha particle, $q_a=2e$

Mass of proton, $m_p=1.67\times 10^{-27}\ kg$

Mass of alpha particle, $m_a=4m_p=6.68\times 10^{-27}\ kg$

The distance of closest approach for two charged particle is given by :

$r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}$

$r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}$

$r=1.91\times 10^{-14}\ m$

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3 years ago

A pendulum is used in a large clock. The pendulum has a mass of 2 kg. If the pendulum is moving at a speed of 2.9 m/s when it re

Rufina [12.5K]

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$E_m=Ek=\frac{1}{2}mv^2$
Where m is the mass of the pendulum. Because of conservation of energy, the total energy at maximum height won't change, but at this point the energy will be purely potential energy instead.
$E_m=E_p$
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4 0

3 years ago

Read 2 more answers

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mart [117]

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

$\lambda=\frac{v}{f}$