Like a then it would be A something I guess it goes like that
Each ball :
P = m * m/sec
P = 1.0 * 5
P = 5.0 kg.m/sec
in stationary :
P = 1.0 kg * 0.0
P = 0.0 kg.m/sec
hope this helps!
Answer:
The minimum frequency is 702.22 Hz
Explanation:
The two speakers are adjusted as attached in the figure. From the given data we know that
=3m
=4m
By Pythagoras theorem
Now
The intensity at O when both speakers are on is given by
Here
- I is the intensity at O when both speakers are on which is given as 6
- I1 is the intensity of one speaker on which is 6
- δ is the Path difference which is given as
- λ is wavelength which is given as
Here
v is the speed of sound which is 320 m/s.
f is the frequency of the sound which is to be calculated.
where k=0,1,2
for minimum frequency , k=1
So the minimum frequency is 702.22 Hz
Answer:
1.45m
Explanation:
Detailed explanation and calculation is shown in the image below
This would most likely be considered speed.