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3 years ago

4x+2y=10 and x-y=13 Use transitive property

1 answer:

mote1985 [20]3 years ago

5 0

Move 4x to the other side
2y=10+4x
Divide both sides by 2y
Y=5+4x

2. X-y=13
Move the first variable to the other side
-y=13+x

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Find the intersection point between the lines of equations: 2x-y+6=0 and 2x+3y-6=0

Ugo [173]

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

$\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0$

On subtracting the given equations we have,

$\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3$

Put this value in any equation , we have ,

$\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5$

Hence the lines will Intersect at ,

$\implies\underline{\underline{ Point=(-1.5, 3)}}$

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2 years ago

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Corey is 66 inches tall. At noon, Corey casts a shadow 108 inches long. At the same time, a tree casts a shadow 216 inches long.

Usimov [2.4K]

This is the term used to describe economic systems in which the basic economic questions are answered based on a socially, pre-established way.

4 0

3 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

Yuki888 [10]

$d=v \cdot t$
d - distance
v - speed
t - time

Car A:
$v_1 \\
t_1=2 \\
d_1=v \cdot 2=2 v$

Car B:
15 mph faster than car A
$v_2=v_1+15 \\ t_2=1.5 \\ d_2= (v_1+15) \cdot 1.5=1.5v_1 + 22.5$

Both cars traveled equal distances:
$d_1=d_2 \\
2v_1 = 1.5v_1+22.5 \\
2v_1-1.5v_1=22.5 \\
0.5v_1=22.5 \\
v_1=45 \\ v_2=45 + 15 =60$

Car B traveled at the speed of 60 mph.

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3 years ago

The oldest child in a family of four children is twice as old as the yougest. The two middle children are 12 and 15 years old. I

vesna_86 [32]

Answer:

8 years old

Step-by-step explanation:

oldest= 16

8+12+15+16= 51

51/4 = 12.73 ( average)

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3 years ago

A distribution is given as

Arada [10]

If X is uniformly distributed on the interval (0, 12), then its PDF is

$f_X(x) = \begin{cases}\frac1{12} & \text{if }0 < x < 12 \\ 0&\text{otherwise}\end{cases}$

or simply

$f_X(x) = \dfrac1{12} \text{ where } 0 < x < 12$

and the zero-elsewhere case is assumed.

Whether you include 0 and 12 in the domain is irrelevant, since the probability that X = 0 or X = 12 are both zero.

4 0

2 years ago