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muminat
3 years ago
6

1. Explain the changes in the conductivity and the changes in the appearance of the solution as drops of Ba(OH)2 are added. This

acid-base reaction can be written as: Ba(OH)2(aq) + H2SO4(aq) BaSO4(s) + 2H2O(l).
Chemistry
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

See explanation

Explanation:

Conductivity of a solution refers to its ability to conduct electricity. It is a measure of how much the solution can conduct electricity.

Looking at the reaction; Ba(OH)2(aq) + H2SO4(aq) ---------->BaSO4(s) + 2H2O(l)

We can see that the concentration of ions in solution decreases from left to right. As the concentration of ions decreases, the conductivity of the solution decreases accordingly since conductivity of solution depends on the concentration of ions in solution.

Also, the solution appears cloudy as the reaction progresses due to the formation of BaSO4(s).

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Mekhanik [1.2K]

Answer:

- Two black balls: they represent a diatomic molecule composed by two atoms of the same element.

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Explanation:

Hey there!

In this case, according to the given information, we can firstly bear to mind the fact that each ball color represents a different element, for that reason we can tell the following:

- Two black balls: they represent a diatomic molecule composed by two atoms of the same element.

- One black ball and two black balls: they represent a compound formed by two different elements.

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8 0
3 years ago
How many grams od Mg(OH)2 will be needed to neutralize 25 mlod
irina [24]

Answer:

0.0073 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For HCl :

Molarity = 0.010 M

Volume = 25 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 25×10⁻³ L

Thus, moles of HCl :

Moles=0.010 \times {25\times 10^{-3}}\ moles

Moles of HCl  = 0.00025 moles

Considering the reaction shown below as:-

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

2 moles of HCl reacts with 1 mole of Mg(OH)_2

So,

1 moles of HCl reacts with 1/2 mole of Mg(OH)_2

Also,

0.00025 moles of HCl reacts with \frac{1}{2}\times 0.00025 mole of Mg(OH)_2

Mole of Mg(OH)_2 = 0.000125 moles

Molar mass of Mg(OH)_2 = 58.3197 g/mol

Mass = Moles*Molar mass = 0.000125\times 58.3197\ g = 0.0073 g

5 0
3 years ago
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