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jarptica [38.1K]
2 years ago
12

The measure of an angle is 38.1 degrees. What is the measure of its supplementary angle

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
3 0

Answer:

141.9°

Step-by-step explanation:

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Easy question with 20 points
dsp73

Answer:

i got 195 because i rounded the numbers, but i believe the answer is D

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3 years ago
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What is the best next step in the construction of the perpendicular bisector of AB?
Vladimir79 [104]

Answer:

This construction shows how to draw the perpendicular bisector of a given line segment with compass and straightedge or ruler. This both bisects the segment (divides it into two equal parts, and is perpendicular to it. It finds the midpoint of the given line segment.

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3 years ago
Scott likes to run long distances. He can run 20 \text{ km}20 km20, start text, space, k, m, end text in 858585 minutes. He want
aleksandrvk [35]

Answer:

<em>Scott will take 221 minutes to run 52 km</em>

Step-by-step explanation:

<u>Speed</u>

The speed of an object can be calculated with the formula:

\displaystyle v=\frac{d}{t}

Where d is the distance traveled and t is the time taken.

Scott can run d=20 km in 85 minutes. Thus, his speed is:

\displaystyle v=\frac{20}{85}\ km/min

Now he wants to know how many minutes it will take him to run d=52 km. Solving the formula for t:

\displaystyle t=\frac{d}{v}

Since the speed has been already determined:

\displaystyle t=\frac{52}{\frac{20}{85}}

Multiplying by the reciprocal of the denominator:

\displaystyle t=52*\frac{85}{20}

t = 221 min

Scott will take 221 minutes to run 52 km

4 0
3 years ago
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Find the t-value such that the area in the right tail is 0.2 with 5 degrees of freedom.
evablogger [386]

Answer:

0.920

Step-by-step explanation:

To calculate this, we proceed to the t-table

Using degree of freedom 5 and significance level of 0.2, the t-value is 0.920

3 0
3 years ago
eric studied for 17.5 hours for a period of 4.5 days. On the average, how much did he study each day?
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17. 5/4.5 = apx. 3.89


Hope this helps!

7 0
3 years ago
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