Answer:
Step-by-step explanation:
The diameter of each curved path is 200 feet. Since the two curved semi circular paths are equal, they would form a circle. It means that the distance around the two semi circular paths would be the circumference of the circle. Formula for determining the circumference of the circle is π × diameter. It becomes
200 × 3.14 = 628 feet
Total distance around the track would be
300 + 300 + 628 = 1228 feet
5280 feet = 1 mile
1228 feet = 1228/5280 = 0.23 mile
If he runs around the track exactly 15 times, it means that the number of miles covered is
0.23 × 15 = 3.45 miles
Since he will collect $4.50 for every mile he runs, the amount of money that he collected is
4.5 × 3.45 = $15.5
Answer:
122
Step-by-step explanation:
For this case we must build a quotient that, when multiplied by the divisor, eliminates the terms of the divide until it reaches the remainder.
It must be fulfilled that:
Dividend = Quotient * Divisor + Remainder
we have that the remainder is 122.
have a good day
Given 460 
a) convert it into 
=> It means 
and 
1 ft = 0.3048 m
1 gal = 3.78541 l
![460ft^2= [tex]460\frac{ft^2}{gal} = \frac{42.7354m^2}{3.78541l} = 11.2895m^2/l](https://tex.z-dn.net/?f=460ft%5E2%3D%20%5Btex%5D460%5Cfrac%7Bft%5E2%7D%7Bgal%7D%20%3D%20%5Cfrac%7B42.7354m%5E2%7D%7B3.78541l%7D%20%3D%2011.2895m%5E2%2Fl)
m^2[/tex].
b. 
c.Given= 
To find inverse, divide it by 1.
Inverse- 
we are given
absolute value of 2 and 2 3rd and negative 9 over 4
Firstly , we need write it in terms of expression
2 and 2 3rd is
so, we get as
now, we can simplify it
Firstly , we will find common denominator
we can see that
all denominators are same
so, we can combine numerators
..............Answer
Answer:
3.84 * 10^0
Step-by-step explanation
Given the following values;
a = 4.8 × 104 and that b = 8 × 10−3
We are to find the product ab
ab = (4.8 × 10^4)(8 × 10^−3)
ab = (4.8*8)(10^4 * 10^-3)
ab = 38.4 * 10^(4-3)
ab = 38.4 * 10^-1
ab = 3.84 * 10 * 10^-1
ab = 3.84* 10^0
<em>Hence the product in standard form is expressed as 3.84 * 10^0</em>
