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Evgen [1.6K]
3 years ago
8

You happen to know that the coefficient of static friction between your patio table and the ground is 0.42. You decide you want

to move it (45kg) by pushing on it. Are you able to move the table?
Physics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

If the force applied is larger than 185.2 N, yes.

Explanation:

In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

F_f = \mu mg

where

\mu=0.42 is the coefficient of static friction

m=45 kg is the mass of the table

g=9.8 m/s^2 is the gravitational acceleration

Substituting,

F_f=(0.42)(45 kg)(9.8 m/s^2)=185.2 N

So, we are able to move the table if we push with a force larger than 185.2 N.

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hodyreva [135]

Answer:

B) 10 minutes

Explanation:

When the size of the problem is 100 then it takes 1 minute to solve

100\ s=1\ min

So, when the size of the problem is 1 then it takes the following minutes

1\ s=\frac{1}{100}\ min

For when the size of the problem is 1000 we have

1000\ s=\frac{1000}{100}\ min=10\ min

So, it will take 10 minutes to solve the algorithm of size 1000

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3 years ago
Hello guys I have a quick question and please help me! Thanks!
xenn [34]

Answer: 4 herz is the answer!

Explanation:

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sometimes sunset could sometimes cause a pink and orange cloud

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3 years ago
Help! PROJECTILE PROBLEM: A 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25
dsp73
Here, 

height at failure, h1 = 525 m, 
upward acceleration, a = 2.25 m/s^2, 
velocity = v m/s, 
<span>
SO, </span>
<span>
v^2 = 2*a*h = 2*2.25*525 = 2362.5 </span>
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<span>
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Hence, 
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a) </span>
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3 years ago
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If I connect an inductor (L) to a capacitor (C), I will get an LC oscillator circuit with some natural frequency omega. If I wer
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The new natural frequency would be ω/2.

we know that,

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now, when capacitance is quadrupled,

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f' = \frac{1}{2 pi (2)\sqrt{LC} }.           -> equation 2

substituting value of equation 1 in equation 2 , we get,

f' = \frac{w}{2}

Hence, the new natural frequency of the circuit is ω/2.

what do you mean by frequency ?

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Learn more about frequency here:-

brainly.com/question/12530980

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