An object of weight W is in freefall close to the surface of Earth. The magnitude of the force that the object exerts on Earth i
2 answers:
Answer:
Equal to W
Explanation:
It is given that, an object of weight W is in free fall close to the surface of Earth. Weight of an object is equal to the product of its mass and acceleration. On the surface of Earth, the weight is given by :
The magnitude of the force that the object exerts on Earth is equal to W as per the Newton's third law of motion. The force exerted from one object to another object must be equal to and opposite to the force exerted from object 2 to 1.
So, the correct option is (c) "equal to W".
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<h2>Hello!</h2>
The answer is:
The first option, the walker traveled 360m more than the actual distance between the start and the end points.
Why?
Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).
So, calculating we have:
Traveler:
Actual distance between the start and the end point (displacement):
Now, to calculate how much farter did the traveler walk, we need to use the following equation:
Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.
Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.
Have a nice day!