An object of weight W is in freefall close to the surface of Earth. The magnitude of the force that the object exerts on Earth i
2 answers:
Answer:
Equal to W
Explanation:
It is given that, an object of weight W is in free fall close to the surface of Earth. Weight of an object is equal to the product of its mass and acceleration. On the surface of Earth, the weight is given by :
The magnitude of the force that the object exerts on Earth is equal to W as per the Newton's third law of motion. The force exerted from one object to another object must be equal to and opposite to the force exerted from object 2 to 1.
So, the correct option is (c) "equal to W".
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Answer:
d) 0 V
Explanation:
It can be showed that the potential due to a point charge q, to a distance d from the charge, can be expressed as follows:
where k =
As the potential is an scalar, and is linear with the charge, we can apply the superposition principle, which means that we can find the potential due to one of the charges, as if the other were not present.
By symmetry, all four charges are at the same distance from the center, so we can write the total potential, as follows:
where d, is the semi-diagonal of the square, that we can find applying Pythagorean theorem, as follows:
Replacing by the values in (1) we have:
which is equal to the option d).