Answer:
slader app helps
Step-by-step explanation:
Answer:
<h2>Perimeter: 16x + 16</h2><h2>Area: 40x + 15</h2>
Step-by-step explanation:
![l-\text{length}\\\\w-\text{width}\\\\\text{The formula of a perimeter of a rectangle:}\ P=2(l+w)\\\text{The formula of an area of a rectangle:}\ A=lw\\\\\text{We have}\ l=8x+3\ \text{and}\ w=5.\\\text{Substitute:}\\\\P=2(8x+3+5)\\P=2(8x+8)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\P=(2)(8x)+(2)(8)\\\boxed{P=16x+16}\\\\A=(8x+3)(5)\qquad\text{use the distributive property}\\A=(8x)(5)+(3)(5)\\\boxed{A=40x+15}](https://tex.z-dn.net/?f=l-%5Ctext%7Blength%7D%5C%5C%5C%5Cw-%5Ctext%7Bwidth%7D%5C%5C%5C%5C%5Ctext%7BThe%20formula%20of%20a%20perimeter%20of%20a%20rectangle%3A%7D%5C%20P%3D2%28l%2Bw%29%5C%5C%5Ctext%7BThe%20formula%20of%20an%20area%20of%20a%20rectangle%3A%7D%5C%20A%3Dlw%5C%5C%5C%5C%5Ctext%7BWe%20have%7D%5C%20l%3D8x%2B3%5C%20%5Ctext%7Band%7D%5C%20w%3D5.%5C%5C%5Ctext%7BSubstitute%3A%7D%5C%5C%5C%5CP%3D2%288x%2B3%2B5%29%5C%5CP%3D2%288x%2B8%29%5Cqquad%5Ctext%7Buse%20the%20distributive%20property%3A%7D%5C%20a%28b%2Bc%29%3Dab%2Bac%5C%5CP%3D%282%29%288x%29%2B%282%29%288%29%5C%5C%5Cboxed%7BP%3D16x%2B16%7D%5C%5C%5C%5CA%3D%288x%2B3%29%285%29%5Cqquad%5Ctext%7Buse%20the%20distributive%20property%7D%5C%5CA%3D%288x%29%285%29%2B%283%29%285%29%5C%5C%5Cboxed%7BA%3D40x%2B15%7D)
Answer:
y=9
y=1
y= -7
y= -15
Step-by-step explanation:
You have to use the number in the x colum and fill in itnot te equation
y= -4x+1
Start with the first number, -2
y= -4(-2)+1 multiply -4 and -2 because of PEMDAS
y=8+1 simplify
y=9
Now do the next number, 0
y= -4(0)+1 Multiple -4 and 0 because of PEMDAS (Anything times 0 is 0)
y=1
Now do the next number, 2
y= -4(2) + 1 Multiply -4 and 2 because of PEMDAS
y= -8 + 1 Simplify
y=-7
Now do the next number, 4
y= -4(4) +1 Multiply -4 and 4 because of Pemdas
y = -16 +1
y= -15
it equals <span>(−<span>12</span>)</span> because <span><span>cos<span>(<span>60∘</span>)</span></span>=<span>12</span></span>
Explanation:
The reference angle for <span>240∘</span> is <span>60∘</span> (since <span><span>240∘</span>=<span>180∘</span>+<span>60∘</span></span>)
<span>60∘</span> is an angle of one of the standard triangles with
<span><span>cos<span>(<span>60∘</span>)</span></span>=<span>12</span></span>
<span>240∘</span> is in the 3rd quadrant so (either by CAST or noting that the "x-side" of the associate triangle is negative)
<span><span>cos<span>(<span>240∘</span>)</span></span>=−<span>cos<span>(<span>60∘</span>)</span></span></span>
<span><span>cos<span>(<span>240∘</span>)</span></span>=−<span><span>12</span></span></span>