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Alex
2 years ago
7

Hi! Is there anyone good with finding the surface area of something? If so, please comment. If you do help me, I will give you 5

star every time you help.
Mathematics
1 answer:
Aleks [24]2 years ago
7 0
No sorry 123
God bless you
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Endpoint given the Midpoint: * The midpoint of RP is M(2, 4). If one of the end points is R(-1,7), find the coordinates of the o
marin [14]

Answer:

The coordinates of other point are: (5,1)

Step-by-step explanation:

Given coordinates are:

M(x,y) = (2,4)

R(x_1,x_2) = (-1,7)

We have to find the coordinates of other point (x2,y2)

The formula for mid-point is given by:

M(x,y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Putting the values we get

(2,4) = (\frac{-1+x_2}{2}, \frac{7+y_2}{2})

Putting respective elements equal

\frac{-1+x_2}{2} = 2\\-1+x_2 = 2*2\\-1+x_2 = 4\\x_2 = 4+1\\x_2 = 5\\And\\\frac{7+y_2}{2} = 4\\7+y_2 = 4*2\\7+y_2 = 8\\y_2 = 8-7\\y_2 = 1

Hence,

The coordinates of other point are: (5,1)

8 0
2 years ago
What is the mean of 5, 8, 16, 22, 19, 27, 32? (Round to the nearest whole number.)
Artyom0805 [142]

Answer:

B) 18.

Step-by-step explanation:

Add them up then divide by the amount of numbers there are.

7 0
3 years ago
Read 2 more answers
A woman is randomly selected from the 18-24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally
dybincka [34]

Answer:

0.0274

Step-by-step explanation:

The mean is \mu =114.8 and the standard deviation is \sigma =13.1.

Calculate

Z=\dfrac{X-\mu}{\sigma}

for X=140:

Z=\dfrac{140-114.8}{13.1}\approx 1.9237.

If X\sim N(114.8,\ 13.1), then Z\sim N(0,1)

and

Pr(X>140)=Pr(Z>1.9237).

Use table for normal distribution probabilities to get that

Pr(Z>1.9237)=1-Pr(Z\le 1.9237)=1-0.9726=0.0274.

7 0
3 years ago
Read 2 more answers
Solve for d when 2x-2yd=y+xd ...?
11Alexandr11 [23.1K]
2x-2yd=y+xd 2x-y=xd+2yd 2x-y=d(x+2y) (2x-y)/(x+2y)=d So the answer is <span><span>d=<span><span>2x−y</span><span>x+2y</span></span></span></span>
3 0
2 years ago
A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th
Ugo [173]

Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

(8 + 9 + 10 + 13 + 14 + 16 + 17 + 20 + 21)/9 = 14.2

a)

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 1.96 × 2.8/√9

= 14.2 ± 1.96 × 0.933

= 14.2 ± 1.83

The lower end of the confidence interval is 12.37

The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

3 0
2 years ago
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