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3 years ago

What is the equation of 35?

Mathematics

2 answers:

Dominik [7]3 years ago

7 0

35 - X = 5

Simplifying

35 + -1X = 5

Solving

35 + -1X = 5

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-35' to each side of the equation.

35 + -35 + -1X = 5 + -35

Combine like terms: 35 + -35 = 0

0 + -1X = 5 + -35

-1X = 5 + -35

Combine like terms: 5 + -35 = -30

-1X = -30

Divide each side by '-1'.

X = 30

Simplifying

X = 30

stira [4]3 years ago

7 0

Answer:

attach a photo

Step-by-step explanation:

i need more detail and then ill answer because there cant be a equation without a problem

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aliina [53]

Answer:What the question?

Step-by-step explanation:

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3 years ago

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3 0

3 years ago

For questions 8 – 14, use the following functions:

pogonyaev

we are given

$f(x)=5$

$g(x)=\sqrt{x+2}$

(8)

$(f+g)(x)=f(x)+g(x)$

we can plug it

$(f+g)(x)=5+\sqrt{x+2}$

(9)

$(f-g)(x)=f(x)-g(x)$

we can plug it

$(f-g)(x)=5-\sqrt{x+2}$

(10)

$(f*g)(x)=f(x)*g(x)$

we can plug it

$(f*g)(x)=5\sqrt{x+2}$

(11)

$(\frac{f}{g} )(x)=\frac{f(x)}{g(x)}$

we can plug it

$(\frac{f}{g} )(x)=\frac{5}{\sqrt{x+2}}$

(12)

$(\frac{g}{f} )(x)=\frac{g(x)}{f(x)}$

we can plug it

$(\frac{g}{f} )(x)=\frac{\sqrt{x+2}}{5}$

(13)

$(fog)(x)=f(g(x))$

$f(x)=5$

we can replace g(x)

we get

$(fog)(x)=5$

(14)

$(gof)(x)=g(f(x))$

$f(x)=5$

we can replace f(x)

$(gof)(x)=\sqrt{f(x)+2}$

we get

$(gof)(x)=\sqrt{5+2}$

$(gof)(x)=\sqrt{7}$

8 0

3 years ago

Write an equation in slope intercept form for the line that passes through (-20,-6) with slope m=1/4

brilliants [131]

We start with the equation y-y1 =m (x-x1) because we have m the slope = 1/4 and a point on the line with the coordinates (x1=-20, y1=-6) so,

y+6=1/4 ( x+20);
y=(1/4)x + 20/4 -6;

y= (1/4)x -1 and this is the equation in slope intercept form y=mx +b where the lope m= 1/4 and b= -1 the y-intercept

Answer y= (1/4)x -1

5 0

4 years ago

Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised t

zimovet [89]

Answer:

(b) 1/792

Step-by-step explanation:

The complete question is;

Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.

(a) How many different groups of 5 problems can be chosen from the 12

problems?

(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?

In (a)

Apply the formula

$\frac{n!}{(n-r)!(r!)}$

where n=12 and r=5

substitute values

$=\frac{12!}{(12-5)!(5!)} \\\\\\=\frac{12!}{(7!)(5!)} \\\\\\=\frac{12*11*10*9*8}{5*4*3*2*1} \\\\\\=\frac{95040}{120} \\\\\\=792$

In (b)

If Jerry did only 5 problems of one assignment then the probability will be

$\frac{5}{12} *\frac{4}{11} *\frac{3}{10} *\frac{2}{9} *\frac{1}{8} =\frac{1}{792}$

4 0

4 years ago

What is the equation of 35?​

What is the equation of 35?