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melomori [17]
3 years ago
8

Explain why 1/6 hour + 1/3 hour =1/2 hour​

Mathematics
2 answers:
Lilit [14]3 years ago
5 0

Answer:

1/6+1/3

=3+6/6×3

=9/18

=1/2

Step-by-step explanation:

Hope you find this helpful!

Brrunno [24]3 years ago
4 0

Answer: It does because 1/3 is equal to 2/6. in order to add them, they have to have the same denominator. and if you add 2/6 to 1/6, you get 3/6. 3/6 is also equal to 1/2, if you divide both sides by 3.

Step-by-step explanation:

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Solve the following system of equations algebraically... NEED HELP PLZ
lana [24]

Answer:

flour $42 , bag of sugar $58

Step-by-step explanation:

let f represent flour and s represent sugar, then

7f + 5s = 584 → (1)

5f + 3s = 384 → (2)

Multiplying (1) by 3 and (2) by - 5 and adding will eliminate s

21f + 15s = 1752 → (3)

- 25f - 15s = - 1920 → (4)

Add (3) and (4) term by term to eliminate s , that is

- 4f = - 168 ( divide both sides by - 4 )

f = 42

Substitute f = 42 into either of the 2 equations and solve for s

Substituting into (1)

7(42) + 5s = 584

294 + 5s = 584 ( subtract 294 from both sides )

5s = 290 ( divide both sides by 5 )

s = 58

The cost of a bag of flour is $42 and cost of sugar is $58

3 0
3 years ago
Mr. Livingston drove 375 miles using g gallons of gas. Write an
svlad2 [7]

Answer:

sdf ss shesty summer

Step-by-step explanation:

sheisty summer

6 0
3 years ago
Plz 30 points im desperate
loris [4]

Answer:

See below for answers and explanations

Step-by-step explanation:

Your table is a little weird, so I will try my best:

a) A linear regression equation for the line of best fit would be y-hat = 0.018x - 24.5111 where y-hat is the predicted value for the recorded weight gain (in pounds) and x is the additional daily caloric intake. You can put the data into lists and use the LinReg function on the TI-84 to get this equation.

b) It seems that as the pony's additional calorie intake increases, the weight gain also increases in pounds

c) Set x equal to 2300 and solve for y-hat:

y-hat = 0.018x - 24.5111

y-hat = 0.018(2300) - 24.5111

y-hat = 41.4 - 24.5111

y-hat = 16.8889

So our predicted value for the weight gain based on an additional 2300 calorie intake is 16.9 pounds.

3 0
3 years ago
Read 2 more answers
Santa Claus is assigning elves to work an eight-hour shift making toy trucks. Apprentice earn five candy canes per hour but can
dimaraw [331]

Answer:

  (a) 5 senior, 4 apprentice

  (b) 368 per shift

  (c) 7.5 senior, 0 apprentice

Step-by-step explanation:

The problem can be described by two inequalities. On describes the limit on the number of elves in the shop; the other describes the limit on the total payroll. Let x and y represent the number of apprentice and senior elves, respectively. Then the inequalities for the first scenario are ...

  x + y ≤ 9 . . . . . . . . . . . . total number of elves in the shop

  5x +8y ≤ 480/8 . . . . . . candy canes per hour paid to elves

These two inequalities are graphed in the first attachment. They describe a solution space with vertices at ...

  (x, y) = (0, 7.5), (4, 5), (9, 0)

__

(a) Santa wants to  maximize the output of trucks, so wants to maximize the function t = 4x +6y.

At the vertices of the solution space, the values of this function are ...

  t(0, 7.5) = 45

  t(4, 5) = 46

  t(9, 0) = 36

Output of trucks is maximized by a workforce of 4 apprentice elves and 5 senior elves.

__

(b) The above calculations show 46 trucks per hour can be made, so ...

  46×8 = 368 . . . trucks in an 8-hour shift

__

(c) The new demands change the inequalities to ...

  x + y ≤ 8 . . . . . . number of workers

  7x +8y ≤ 60 . . . total wages (per hour)

The vertices of the feasible region for these condtions are ...

  (x, y) = (0, 7.5), (4, 4), (8, 0)

From above, we know the truck output will be maximized at the vertex (x, y) = (0, 7.5). However, we know we cannot have 7.5 senior elves working in the shop. We can have 7 or 8 elves working.

If the workforce must remain constant, truck output is maximized by a workforce of 7 senior elves.

If the workforce can vary through the shift, truck output is maximized by adding one more senior elf in the shop for half a shift.

Santa should assign 7 senior elves for the entire shift, and 8 senior elves (one more) for half a shift.

_____

<em>Comment on apprentice elf wages</em>

At 5 candy canes for 4 trucks, apprentice elves produced trucks for a cost of 1.25 candy canes per truck. At 8 candy canes for 6 trucks, senior elves produced trucks for a cost of about 1.33 candy canes per truck. The reason for employing senior elves in the first scenario is that their productivity is 1.5 times that of apprentice elves while their cost per truck is about 1.07 times that of apprentice elves.

After the apprentice elves wages were increased, their cost per truck is 1.75 candy canes per truck, but their productivity hasn't changed. They have essentially priced themselves out of a job, because they are not competitive with senior elves.

5 0
2 years ago
if you wish to calculate the interest on an investment with a rate of 6.17%, what number will you plug into your equation?
Kitty [74]
The number used for the interest rate will be 6.17% in decimal form: 0.0617.
3 0
3 years ago
Read 2 more answers
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