Answer:
Option a, b, d, f, and j is legal method calls.
Explanation:
In the given question some information is missing, that is the method definition which can be described as follows:
Method definition:
int x =2, y=3; //defining integer variable
int mathMethod (int x) //method definition
{//method body
int z=x+y; //calculate value
return z; //return value
}
In the given question option a, b, d, f, and j is legal, because these options follow the correct syntax, and other option were incorrect which can be defined as follows:
- In option c, It is illegal because it accepts only one parameter.
- In option e, It is accepts long number, that's why it is illegal.
- In option g, It accepts float value, that's why it is illegal.
- In option h, It doesn't accepts any parameter.
- In option i, It isn't use in method.
0, a square has 4 right angles
I believe that would be authorization.
I = 0
while( i < ( n * 2 ) ):
s += '*'
i += 1
