Ask question

Ask question

All categories

3 years ago

5

The deepest part of a swimming pool is 12 feet deep. The shallowest part of the pool is 3 feet deep. What is the ratio of the de

pth of the deepest part of the pool to the depth of the shallowest part of the pool?

1 answer:

ivolga24 [154]3 years ago

6 0

I think the ratio is 4:1

You might be interested in

Above is a table that gives the interest per every $100 financed. Use the table to determine the annual percentage rate for a 11

Sladkaya [172]

13 percent , just took the quiz

4 0

3 years ago

Help me out please!!!!

KonstantinChe [14]

Answer:

c)

Step-by-step explanation:

$- \frac{7}{ - f} \: is \: equal \: to \: \frac{7}{f}$

$so \: the \: answer \: is \: none \: of \: the \: above$

7 0

3 years ago

Read 2 more answers

If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2

alukav5142 [94]

Answer:

The transformed points of the triangle ABC are $A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$ , $B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$ , $C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

$A' (x,y) = \frac{1}{2}\cdot (1,1)$

$A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$

$B' (x,y) = \frac{1}{2}\cdot (9,1)$

$B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$

$C'(x,y) = \frac{1}{2}\cdot (1,9)$

$C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

7 0

3 years ago

A parallelogram has a base of 4 and height of 7x-2. If the area of the parallelogram is 96 square units, what is the value of x

r-ruslan [8.4K]

I think will be B yes

4 0

2 years ago

43. g(x) = 2x + 5<br><br>find the function values

OleMash [197]

Answer:

G(x)= x^2 +5x +C

Step-by-step explanation:

5 0

2 years ago