Answer:
A)
<u>4, 7, 4, 6</u>
B)
<u>12 moles</u>
Explanation:
![NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)](https://tex.z-dn.net/?f=%20NH_%7B3%7D%28g%29%20%2B%20O_%7B2%7D%28g%29%20%5C%3A%20%E2%86%92%20NO_%7B2%7D%20%2B%20H_%7B2%7DO%28g%29)
__↑______↑
8.00 mol | 14.00 mol
________________
![NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)](https://tex.z-dn.net/?f=%20NH_%7B3%7D%28g%29%20%2B%20O_%7B2%7D%28g%29%20%5C%3A%20%E2%86%92%20NO_%7B2%7D%20%2B%20H_%7B2%7DO%28g%29)
You can turn this into a system of variables which are solvable.
To do this, create variables for the coefficients of each compound in the reaction respectively.
![a(NH_{3}(g)) + b(O_{2}(g)) → \\c(NO_{2}) + d(H_{2}O(g))](https://tex.z-dn.net/?f=%20a%28NH_%7B3%7D%28g%29%29%20%2B%20b%28O_%7B2%7D%28g%29%29%20%E2%86%92%20%5C%5Cc%28NO_%7B2%7D%29%20%2B%20d%28H_%7B2%7DO%28g%29%29)
Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.
a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.
(Reactant = Product)
Reactant: 1a [N] Product: 1c.
Reactant: 3a [H] Product: 2d.
Reactant: 2b [O] Product: 2c + 1d.
Thus the system is:
1a = 1c
3a = 2d
2b = 2c + 1d.
Then just use the substitution methods to solve.
Answer:
Explanation:
Cu²⁺ + 2e⁻ → Cu ( copper gets reduced )
Cu → Cu²⁺ + 2e⁻ ( copper gets oxidized )
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
Answer: varriable
Explanation:meaning one element, feature or factor able to change
I think it would be the sun because it’s the one giving energy to most things, and if you haven’t answered it yet you can put the sun because it’s giving energy to the plans and the environment and it’s the the sun was the effect of the whole thing, sorry if I didn’t help
Answer:
A
Explanation:
In a cold front set-up, the boundary between the cold and warm air masses is relatively steep, typically causing the warm air in front of it to rise rapidly.