Tap water used for drinking is considered in the DIL calculations; true
Answer:
58mL
Explanation:
Given parameters:
Density of water = 1g/mL
Mass of object = 58g
Unknown:
The volume the object must have to be able to float in water = ?
Solution:
To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.
We then set its density to that of water;
Density =
Volume =
So;
Volume =
= 58mL
Answer:
crushing an ice cube
Explanation:
crushing an ice cube can be redone by freezing it again in its position
Melting, vaporization, boiling, and sublimation.