Answer:
- The sequence is an Arthemtic Progression
An=A1+(n-1)d
A1 is first term, An is nth term, n is number of term, and d is common difference
therefore
A4=35, A1= -17
A4=A1+(4-1)d
35= -17+3d
35+17=3d
52=3d
52/3=3d/3
14=d
common diffrence(d)=14
- The general solution is given by
An= -17+(n-1)14
An= -17+14n-14
An= -31+14n
<u>An= 14n-31</u>
A14 term, means n=14
From An=A1+(n-1)d
A14= -17+(14-1)14
= -17+(13×14)
= -17+182
= 165.
<u>Therfore, the 14th term is 165.</u>
2. A sequence has a CR of 4/5 and its eighth term (a8) is (393216/3125). What is its general equation? Its 3rd term?
<u>solution</u>
common ratio(r)=4/5
eighth term(G8)=393216/3125
From Gn= G1r^(n-1)
G8 means n=8
G8=G1r^(n-1)
393216/3125=G1(4/5)^(8-1)
393216/3125=G1(4/5)^7
G1=(393216/3125)/(4/5)^7
G1=600
<u>The first term is given by G1=600</u>
The General equation is given by
The General equation is given by Gn= 600(4/5)^(n-1)
3rd term (G3)
G3= G1(4/5)^(3-1) where n=3,
=600(4/5)^2
=600(16/25)
=384
<u>Therefore, the 3rd term is given by G3= </u><u>3</u><u>8</u><u>4</u><u>.</u>
<u>I</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u><u>m</u><u>a</u><u>d</u><u>e</u><u> </u><u>s</u><u>o</u><u>m</u><u>e</u><u> </u><u>C</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u>s</u><u> </u><u>i</u><u> </u><u>m</u><u>e</u><u>s</u><u>s</u><u>e</u><u>d</u><u> </u><u>u</u><u>p</u><u> </u><u>s</u><u>o</u><u>m</u><u>e</u><u>w</u><u>h</u><u>e</u><u>r</u><u>e</u><u>.</u>
Answer: 1.8 s
Step-by-step explanation:
Given
The height of the spring mass system above the table is given by

The mass is performing S.H.M with frequency 
and 

time when mass returns to its original position

21 and 22 because 21+22=43
In an isosceles triangle, the base angles are congruent. The third angle is called the vertex angle.
Here, the vertex angle is <A.
Therefore, m<C = m<B.
m<A = 3m<B + 20
m<A + m<B + m<C = 180
3m<B + 20 + m<B + m<B = 180
5m<B + 20 = 180
5m<B = 160
m<B = 32
m<C = m<B = 32
Answer: m<C = 32 deg