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tester [92]
3 years ago
14

Find the value of m and b for the equation 0=-9x+5y+25

Mathematics
1 answer:
lukranit [14]3 years ago
8 0

Answer:

X= -5

Y=-2.7

Step-by-step explanation:

YOU DO THIS BY SUBTRACTING 25 ON THE RIGHT SIDE TO THE LEFT ONLY LEAVING YOU WITH VARIABLES.

THEN YOU SUBSTITUTE ZERO INTO Y TO FIND X THEN SUBTITUTE ZERO INTO X TO FIND Y

BTW SUBSTITUTE ONE INTO THE VARIABLE YOU ARE FINDING

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I need help please, i don’t not understand
Leviafan [203]
Write in 0 and 0 at the top:  this indicates that if there are zero pennies, the height of the tower is 0.  This is the point (0,0).  Another point is (4, 28):  a tower of 28 pennies is 4 cm tall.

Find the slope of the line connecting (0,0) and (4,28).
            4cm - 0 cm
    m = ----------------- = (1/7) (cm/penny)
            28 - 0

The equation we need, relating # of pennies to height of tower, is 

       t = (1/7) (cm/penny)x, where x is the # of pennies.

Thus, if x = 1, then t=1/7 cm

And, if x =15, then t = 15/7 cm

And so on.
7 0
4 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
3 years ago
Find the equation of the axis of symmetry of the parabola.
Stolb23 [73]

Answer:

Just substitute 0 instead of f (x),therefore

x { }^{2}  - 12x + 36 \\ x = 6

The answer option is C

7 0
3 years ago
ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x
fomenos

Answer:

A) x = 20

Step-by-step explanation:

ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.

Since, diagonals of a rhombus are perpendicular bisector.

\therefore \: m \angle AED = 90 \degree \\  \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90  \\ \therefore \: 5x  = 90 + 10  \\ \therefore \: 5x  = 100  \\ \\  \therefore \: x  = \frac{100}{5}  \\  \\ \huge \red{ \boxed{ \therefore \: x  =20}}

5 0
3 years ago
Solve the inequality and graph its solution: 6n – 11 &gt; 31
miss Akunina [59]
<span>6n – 11 > 31
</span><span>6n  > 31 + 11
</span>6n  > 42
  n > 42/6
  n > 7
5 0
3 years ago
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