2 years ago

In Figure 4.27 four particles form a square of edge length

Physics

1 answer:

Shalnov [3]2 years ago

8 0

Answer:

so sorry

don't know but please mark me as brainliest please

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Which of the following electron configurations for neutral atoms is correct?

liq [111]

Nitrogen: 1s2, 2s2, 2p3 is correct answer.

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3 years ago

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Which items do NOT describe possible solutions to air pollution?

bonufazy [111]

Answer:

2, 6

Explanation:

2 because if you cut down more trees you will have less items to help collect co2

6 because if you have more manufracturing more gasses will be release and moe carbon dioxcide in the air so it will slowly kill the ozone layer.

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3 years ago

What is the resistance of a 3.5 m copper wire (Rho= 1.7x10-8 Ohm·m) that 1 point

VikaD [51]

Answer:

(D)

Explanation:

Given :

l=3.5 m

$A=5.26*10^{-6}$ $m^{2}$

$p=1.7*10^{-8} ohm.m$

Resistance can be calculated as :

$R=p\frac{l}{A} \\R=1.7*10^{-8} \frac{3.5}{5.26*10^{-6} }$

$R=\frac{5.95*10^{-2} }{5.26} \\R=1.13*10^{-2}$

Resistance of the wire will be 1.1× $10^{-2}$ ohms

Option D is correct

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2 years ago

The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 1% per day. A s

Bumek [7]

Answer:

2,38kg

Explanation:

Mass in function of time can be found by the formula: $m_{(t)} =m_{0} e^{-kt}$ , where $m_{0}$ is the initial mass, t is the time and k is a constant.

Given that a sample decay 1% per day, that means that after first day you have 99% of mass.

$m_{(1)} =m_{0} e^{-k(1)}$ , but $m_{(1)}=\frac{99m_{0} }{100}$ , so we have $\frac{99m_{0} }{100}=m_{0}e^{-k}$ , then $k=-ln(\frac{99}{100})=0.01$

Now using k found we must to find $m_{(5)}$ .

$m_{(5)}=m_{0}e^{-(0.01)5}=2.5kge^{-0.05} =2.5x0.951=2.38kg$

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3 years ago

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The radius is higher than the refraction

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