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2 years ago

Determine the maximum r-value of the polar equation r =3+3 cos 0

Physics

2 answers:

AURORKA [14]2 years ago

8 0

[r] =6

Solve for r by simplifying both sides of the equation, then isolating the variable.

<em> </em>I hope this makes sense

m_a_m_a [10]2 years ago

5 0

Answer:

|r|= 6

Explanation:

Looking at cosine function , it has a maximum value of 1 at θ= 2π

r= 3+3cosθ

r= 3+3cos(2π)

r= 3+3(1)

r=3+3

r=6

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Answer:

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From the figure,

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Also, $r=l\ sin\theta$

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$T=\dfrac{2\pi r}{v}$

Put the value of T from equation (2) to the above expression:

$T=\dfrac{2\pi r}{\sqrt{gl\ tan\theta.sin\theta}}$

$T=\dfrac{2\pi l\ sin\theta}{\sqrt{gl\ tan\theta.sin\theta}}$

On solving above equation :

$T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}$

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