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Nataliya [291]
3 years ago
7

5. The starter phase of a fitness program is important because it A. gives a person the opportunity to discover the exercises th

at work best for his or her needs. B. ensures that a person sticks with a certain exercise regimen. C. allows a person to lose a lot of weight quickly. D. makes running easier.
Physics
1 answer:
Orlov [11]3 years ago
4 0

Answer:

The starter phase of a fitness program is important because gives a person the opportunity to discover the exercises that work best for his or her needs. - A.

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Explain about ohm's law.​
belka [17]

Answer:

Statement:

The electric current passing through a conductor is directly proportional to the potential difference across its ends provided temperature and other physical conditions remain constant.

Explanation:

Current is directly proportional to voltage loss through a resistor. That is, if the current doubles, then so does the voltage. To make a current flow through a resistance there must be a voltage across that resistance. Ohm's Law shows the relationship between the voltage (V), current (I) and resistance (R).

V∝I or I∝V⇒V=IR.

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3 years ago
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COULD SOMEONE PLS DO THESE FOR ME <br> I’LL LOVE U FOREVER AND EVER
sladkih [1.3K]
I can help you do them for yourself :)
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3 years ago
Which is an example of current electricity?
anyanavicka [17]

Answer:

c

Explanation:

i think

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3 years ago
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A skydiver is falling at constant velocity. If a force of 600 N is pulling down on the skydiver, how much force must be acting u
skelet666 [1.2K]

Well, if the skydiver is at constant velocity, than there’s no acceleration, as stated by Newton’s first law. Thus the total net force would equate to 0. In order to make this statement true, the answer would have to be exactly 600 N.

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3 years ago
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An electric field of 280000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -
nordsb [41]
<h2>The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.</h2>

Explanation:

Electric field is the ratio of force and charge.

Electric field, E = 280000 N/C

Charge, q = -7.9 C

We have

                 E=\frac{F}{q}\\\\280000=\frac{F}{7.9}\\\\F=280000\times 7.9\\\\F=2.21\times 10^6N

The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.

4 0
3 years ago
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