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nevsk [136]
3 years ago
5

One astronomer believes that the density of the universe remains constant. One physicist believes that the density of the univer

se changes over a period of time. Which of these statements best explains why the astronomer and physicist have different views on the density of the universe?
Most data on density of the universe are inaccurate.

Scientists provide different theories to strengthen science.

Scientists having different interests arrive at different conclusions.

Most experiments on density of the universe cannot be repeated.
Physics
2 answers:
Alex3 years ago
8 0

Answer:

Scientists having different interests arrive at different conclusions.

Explanation:

Science helps society by taking decisions based on investigations, which must be supported by argumentation to become accepted. Therefore, because curiosity and concern are based on inner experience rather than fact, scientists who have different views and arrive at opposite resolutions.

Llana [10]3 years ago
6 0
I think the third option is the answer 
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I believe the best answer is law, as scientific laws are accepted to be true under the proper conditions. 
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Is the process of changing from one phase of matter to another a physical change or a chemical change? Explain why. please asap
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The process of changing from one phase  of matter to another is a physical matter.

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3 years ago
What causes different colors to appear in the sky.
dlinn [17]

Answer:

The colors of the sunset result from a phenomenon called scattering. Molecules and small particles in the atmosphere change the direction of light rays, causing them to scatter. ... The short-wavelength blue and violet are scattered by molecules in the air much more than other colors of the spectrum.

Explanation:

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3 years ago
What is the energy per photon absorbed during the transition from n = 2 to n = 3 in the hydrogen atom?
adelina 88 [10]

Answer : The energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

Explanation :

First we have to calculate the wavelength of hydrogen atom.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 10973731.6 m⁻¹

n_f = Higher energy level = 3

n_i= Lower energy level = 2

Putting the values, in above equation, we get:

\frac{1}{\lambda}=(10973731.6)\left(\frac{1}{2^2}-\frac{1}{3^2} \right )

\lambda=6.56\times 10^{-7}m

Now we have to calculate the energy.

E=\frac{hc}{\lambda}

where,

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 6.56\times 10^{-7}m

Putting the values, in this formula, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{6.56\times 10^{-7}m}

E=3.03\times 10^{-19}J

Therefore, the energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

3 0
3 years ago
An 11.0 -W energy-efficient fluorescent lightbulb is designed to produce the same illumination as a conventional 40.0-W incandes
yarga [219]

The amount or cost that the user of the energy-efficient bulb save during 100h of use will be $0.319.

<h3>How to calculate the cost?</h3>

For the 11.0W bulb, it should be noted that the value will be:

= 11.0 × 100 × (1/1000) × 0.110

= $0.121

The 40W bulb will be:

= 40 × 100 × (1/1000) × 0.110

= $0.44

Therefore, the amount that will be saved will be:

= $0.44 - $0.121

= $0.319

Learn more about cost on:

brainly.com/question/25109150

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6 0
2 years ago
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