Answer:
The speed of the 1 kg red ball 8.04 m/s .
Explanation:
Given :
Separation between rods , d = 1.5 m .
Mass of the red ball is 1 kg .
Mass of the orange ball is 5.7 kg .
Angular velocity ,
.
Now , distance of center of mass from red ball is :
![r =\dfrac{0\times 1+1.5\times 5.7}{1+5.7}\\\\r = 1.28\ m](https://tex.z-dn.net/?f=r%20%3D%5Cdfrac%7B0%5Ctimes%201%2B1.5%5Ctimes%205.7%7D%7B1%2B5.7%7D%5C%5C%5C%5Cr%20%3D%201.28%5C%20m)
We know , speed is given by :
![v=\omega r\\\\v=2 \times \pi \times 1.28\\\\v=8.04\ m/s](https://tex.z-dn.net/?f=v%3D%5Comega%20r%5C%5C%5C%5Cv%3D2%20%5Ctimes%20%5Cpi%20%5Ctimes%20%201.28%5C%5C%5C%5Cv%3D8.04%5C%20m%2Fs)
Hence , this is the required solution .
Answer:
The electric field is directed toward the electron and has a magnitude of
.
Explanation:
An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.
In the given case electron is given and the magnitude of charge on electron is ![e=1.6\times 10^{-19}C](https://tex.z-dn.net/?f=e%3D1.6%5Ctimes%2010%5E%7B-19%7DC)
Electric field can be represented as,
![E=\frac{kQ}{r^{2} }](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BkQ%7D%7Br%5E%7B2%7D%20%7D)
Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.
In the given question an electron is given so electric field will be,
![E=\frac{ke}{r^{2} }](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bke%7D%7Br%5E%7B2%7D%20%7D)
As we know that electric field start from the positive charge and vanish in the negative charge.
So, here the electric field will be
and it is directed toward the electron because of negative charge on the electron.
C.There is an invisible magnetic field around the magnet where it exerts magnetic force