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tester [92]
3 years ago
5

ANSWER THIS FOR BRAINY CROWN B) ITS SO EASY!

Physics
2 answers:
Stolb23 [73]3 years ago
5 0
So, if there’s two collide Non-sticky collision. And there’s 600 KG.M/S for 2 cars they we know that the unit rate is 300/KG.M/S for 1 car.
Luda [366]3 years ago
3 0

Answer:

300

Explanation:

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In a velocity-time graph what is represented by the slope, or steepness of the graph line.
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6 0
3 years ago
Which of the following is the best explanation for speed? *
Ivan

Answer:

how long the object travels in a set amount of time

Explanation:

that's how it got it's si unit m/s

please like and Mark as brainliest

6 0
3 years ago
As a ball is released from 10ft above the ground, it falls freely (without friction)
Masteriza [31]

Answer:

Explanation:

The formula to find Potential Energy is PE = mgh, where m is the mass of the object, g is gravity, and h is the height from which the object can potentially fall. Because this is linear, then PE will increase as either the mass or the height increase (gravity is constant at 9.8 m/s/s). If the mass of the ball being dropped doesn't change, then the only thing that determines this ball's max PE is the height from which it is dropped; max PE ALWAYS occurs at the highest point from which an object can potentially fall. So your answer is "At the top".

7 0
3 years ago
A crow is flying horizontally with a constant speed of 2.70m/s when it releases a claim from its beak. The clan lands on the roc
jenyasd209 [6]

Given:

Speed = 2.70 m

Time, t = 2.10 seconds

Let's solve for the following:

• (a) The horizontal component of the velocity.

To find the horizontal component, apply the formula:

V_{ox}=V_o\cos \theta

Where:

Vo is the initial speed = 2.70 m

θ = 0 degrees

Hence, we have:

\begin{gathered} V_{ox}=2.70\cos 0 \\  \\ V_{ox}=2.7\text{ m/s} \end{gathered}

The horizontal component of the velocity just before it lands is 2.70 m/s.

• (b) The vertical component of the velocity.

To find the vertical component, apply the formula:

V_{oy}=V_{0y}-gt=\text{V}_{oy}\text{ sin}\Theta-gt

Where:

g is the acceleration due to gravity = 9.8 m/s²

t is the time = 2.10 s

Hence, we have:

\begin{gathered} V_{oy}=V_{oy}\sin \theta-gt \\  \\ V_{oy}=2.70\sin 0-9.8(2.10) \\  \\ V_{oy}=0-20.58 \\  \\ V_{oy}=-20.58\text{ m/s} \end{gathered}

The vertical component of the velocity just before it lands is -20.58 m/s.

(c) Here, the initial speed is equal to the constant horizontal speed.

Therefore, in part (a) the horizontal component will increase in the x-direction if the speed of the crow is increased.

The initial vertical velocity is 0 m/s in both cases.

Therefore, in part (b) the vertical component will remain constant.

ANSWER:

(a) 2.70 m/s

(b) -20.58

(c) In part (a) the horizontal component will increase, while in part (b) the vertical component will remain constant.

6 0
1 year ago
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