Answer:
B
Explanation:
took test on edg and got it right
Answer:
Part a)
V = 15 Volts
Part b)
P = 180 Watt
Part c)
Rate = 720 Watt
Explanation:
Part a)
When battery is in charging then the potential difference of the terminals of cell is given by
![\Delta V = EMF + iR](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20EMF%20%2B%20iR)
here we know that
EMF = 12 volts
i = 60 A
r = 0.050 ohm
now we have
![\Delta V = 12 + (0.050)(60) = 15 Volts](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%2012%20%2B%20%280.050%29%2860%29%20%3D%2015%20Volts)
Part b)
Rate of thermal energy dissipated is the energy which is dissipating across the resistor
so here we have
![P = i^2 R](https://tex.z-dn.net/?f=P%20%3D%20i%5E2%20R)
![P = (60^2)(0.05)](https://tex.z-dn.net/?f=P%20%3D%20%2860%5E2%29%280.05%29%20)
P = 180 Watt
Part c)
Rate at which Energy stored inside the cell is the rate of electrical energy that is converted into the chemical energy
![Rate = EMF \times i](https://tex.z-dn.net/?f=Rate%20%3D%20EMF%20%5Ctimes%20i)
![Rate = (12)(60)](https://tex.z-dn.net/?f=Rate%20%3D%20%2812%29%2860%29)
![Rate = 720 Watt](https://tex.z-dn.net/?f=Rate%20%3D%20720%20Watt)