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abruzzese [7]
3 years ago
5

What is not a factor affecting impact in a collision; vehicle weight, speed, kinetic energy, centrifugal force

Physics
1 answer:
navik [9.2K]3 years ago
6 0
I believe the answer is vehicle weight
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Which two objects have stored energy?
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3) a stretched rubber band
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4 years ago
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What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?
Mrac [35]
The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.
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4 years ago
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A disk rotates freely on a vertical axis with an angular velocity of 50 rpm . An identical disk rotates above it in the same dir
True [87]

Answer:

Final angular velocity is 35rpm

Explanation:

Angular velocity is given by the equation:

I1w1i + I2w2i = I1w1f -I2w2f

But the two disks are identical, so Ii =I2

wf can be calculated using

wf = w1i - w2i/2

Given: w1i =50rpm w2i= 30rpm

wf= (50 + 20) / 2

wf= 70/2 = 35rpm

5 0
3 years ago
Max is a network technician who just terminated the ends on a new copper cable used between two legacy switches. When he connect
Olegator [25]

Answer:

The cable used is a straight through cable.

Explanation:

The cable used here is a straight through cable, that is why it fails to establish the connection.

Cross-over cables are used to communicate over legacy switch. It is used to connect computing devices directly.

In a cross over cable, signal gets transmit from one end of the device to the other.

7 0
3 years ago
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
eimsori [14]

Answer:

1) The time it takes the diver to move off the end of the diving board to the pool surface, t_w, is approximately 1.392 seconds

2) The horizontal distance from the edge of the pool to where the diver enters the water, d_w, is approximately 5.76 meters

Explanation:

1) The given parameters are;

The height of the diving board above the pool's surface, h = 9.5 m

The length by which the diving board over hangs the pool L = 2 m

The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s

Taking t_w = The time it takes the diver to move off the end of the diving board to the pool surface

Therefore, we have from the equation of free fall;

h = 1/2 × g × t_w²

Where;

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

9.5 = 1/2 × 9.81 × t_w²

t_w = √(9.5/(1/2 × 9.81)) ≈ 1.392 s

The time it takes the diver to move off the end of the diving board to the pool surface = t_w ≈ 1.392 s

2) The horizontal distance, d_w, in meters from the edge of the pool to where the diver enters the water is given as follows;

d_w = L + v₀ × t_w = 2 + 2.7× 1.392 ≈ 5.76 m

∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.

7 0
3 years ago
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