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Novosadov [1.4K]
3 years ago
8

A bag of ice cubes absorbs 149,000 J of heat, which causes its temperature to increase by 5.23 degrees celsius. what is the mass

of the ice in the bag?
Ice=c=2000J/(kg*c) (unit=kg)
Physics
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

14.3kg

Explanation:

Given parameters:

Quantity of heat = 149000J

Change in temperature = 5.23°C

specific heat of the ice = 2000J/kg°C

Unknown:

Mass of the ice in the bag = ?

Solution:

The heat capacity of a substance is given as:

            H = m c Ф

H is the heat capacity

m is the mass

c is the specific heat

Ф is the temperature change;

  since m is the unknown, we make it the subject of the expression;

                    m = H/ mФ

                  m = \frac{149000}{2000 x 5.23}  = 14.3kg

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a) The x-coordinate of the center of gravity is \frac{19}{18}\cdot a.

b) The y-coordinate of the center of gravity is \frac{19}{18}\cdot a.

<h3>Determination of the coordinates of the center of gravity</h3>

Let suppose that each square has an <em>uniform</em> density, the coordinates of the center of gravity of each square with respect to the origin are, respectively:

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\vec r_{cg} = \frac{(50\,N)\cdot (0.5\cdot a, 0.5\cdot a) + (30\,N)\cdot (1.5\cdot a, 0.5\cdot a)+(30\,N)\cdot (0.5\cdot a, 1.5\cdot a)+(70\,N)\cdot (1.5\cdot a, 1.5\cdot a)}{50\,N+30\,N+30\,N+70\,N}

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\vec r_{cg} = \left(\frac{19}{18}\cdot a, \frac{19}{18}\cdot a  \right) \blacksquare

a) The x-coordinate of the center of gravity is \frac{19}{18}\cdot a. \blacksquare

b) The y-coordinate of the center of gravity is \frac{19}{18}\cdot a. \blacksquare

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