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Vsevolod [243]
3 years ago
5

1. Suppose that you have a mass of 45.7 kg and are standing on frictionless roller skates. Someone then throws you a 2.50 kg mas

s with a velocity of 14.5 m/s and you catch it. What will be your resultant velocity? (0.75 m/s)
Physics
1 answer:
noname [10]3 years ago
4 0
The momentum afterward will be your initial momentum (zero here) plus the momentum of the object 2.5kg*14.5m/s = 36.25kg*m/s.  This will be your final momentum, mv, but now your mass must include the 2.5kg object. so your mass is 45.7+2.5 = 48.2kg.  So mv=36.25 ;  48.2*v=36.25 ; v = 0.752m/s
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Can someone answer these?
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Short Answer

3: C

4: D

Problem Three

Remark

Somewhere we ought to be told that this is the Doppler Effect. I have never done a problem using this formula, so I think I'm doing it correctly, but no guarantees. My guess is that the frequency increases as it comes towards you and decreases as it moves away from you. I think that is correct.

Formula

<em><u>Givens</u></em>

  • f' = observed frequency
  • f = actual frequency
  • v = velocity of sound or light waves.
  • vo = velocity of observer (in both cases 0)
  • vs = velocity of source.

f' = (v + vo) * f / (v - vs)

Solution

  • v = 3*10^8 m/s
  • f' = 1.1 f
  • f = f
  • vo = 0  We are standing still while all this is going on.
  • vs = ???

f'/f = 1.1

1.1 = (3*10^8  + 0 ) / (3*10^8 - vs)

3.3*10^8 - 1.1*vs = 3*10^8

3.3*10^8 - 3*10^8= 1.1 vs

0.3 * 10^8 = 1.1 vs

2.73 * 10^7 = vs

The closest answer is 3.00 * 10^7 which is C

Problem Four

Here what is happening is that you are looking for the frequency resulting from a wave moving towards you at 1/2 the speed of sound. You are not moving.

<em><u>Givens</u></em>

  • v = v
  • vs = 1/2 v
  • f ' = ?
  • f = 1000 hz
  • vo =0

f' = v/(v - 1/2v) * 1000

f' = v/ (1/2 v) * 1000

f' = 2 * 1000

f' = 2000 which is D

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4 years ago
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Answer:

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Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

deduced from the question,

Momentum of the car = momentum of the barrier.

MV = mv ............................. Equation 1

Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

v = MV/m........................ Equation 2

Given: M = 1000 kg, V = 10 m/s, m = 20 kg.

Substitute into equation 2

v = 1000(10)/20

v = 500 m/s.

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