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Vsevolod [243]
3 years ago
5

1. Suppose that you have a mass of 45.7 kg and are standing on frictionless roller skates. Someone then throws you a 2.50 kg mas

s with a velocity of 14.5 m/s and you catch it. What will be your resultant velocity? (0.75 m/s)
Physics
1 answer:
noname [10]3 years ago
4 0
The momentum afterward will be your initial momentum (zero here) plus the momentum of the object 2.5kg*14.5m/s = 36.25kg*m/s.  This will be your final momentum, mv, but now your mass must include the 2.5kg object. so your mass is 45.7+2.5 = 48.2kg.  So mv=36.25 ;  48.2*v=36.25 ; v = 0.752m/s
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Explanation:

Hi there!

The average speed (a.s) is calculated by dividing the traveled distance (d) over the time needed to travel that distance (t):

a.s = d / t

So, let´s find the distance traveled in those 3 s. For that, we can use the equation of position of an object moving in a straight line with constant acceleration:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

If we place the origin of the frame of reference at the point where the runner starts, then, x0 = 0. Since the runner starts from rest, v0 = 0. So, the equation gets reduced to this:

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We have the time (3 s), so let´s find the acceleration. For that, we can use the equation of velocity of an object moving in a straight line with constant acceleration:

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v = a · t

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x = 1/2 · 8/3 m/s² · (3 s)²

x = 12 m

Now, we can calcualte the average speed:

a.s = d/t

a.s = 12 m / 3 s

a.s = 4 m/s

The average speed of the runner is 4 m/s.

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