i think A but if I'm wrong sorry
then if increasing then becoming spread out so letter A
Answer:
There are a variety of methods by which a sample's boiling point can be determined, including distillation, reflux, and by using a Thiele tube. The most straightforward method uses a Thiele tube, and has the advantage of using less than 0.5mL of material.
Distillation Method
There are simpler methods than a distillation to measure a compound's boiling point, and it is recommended to explore other options (e.g. Thiele tube) if this is the only goal. However, if materials are limited, or if a purification is planned anyhow, a distillation can be used to determine a compound's boiling point. The distillation technique is discussed in great detail in Chapter 5.
A simple distillation should suffice for most situations and at least 5mL of sample should be used in the distilling flask along with a few boiling stones or stir bar. As the bulk of the material distills, the highest temperature noted on the thermometer corresponds to the boiling point. A major source of error with this method is recording too low a temperature, before hot vapors fully immerse the thermometer bulb. 5 Be sure to monitor the thermometer periodically, especially when the distillation is active. Record the barometric pressure along with the boiling point.
Reflux Method
A reflux setup can also be used to determine a compound's boiling point. Reflux is when a liquid is actively boiling and condensing, with the condensed liquid returning to the original flask. It is analogous to a distillation setup, with the main difference being the vertical placement of the condenser.
Thiele Tube Method
The answer would be heptan-3-one and heptan-4-one.
The acid-catalyzed hydration of a balanced alkyne gives a
ketone.
R-C≡C-R + H₂O → R-CH₂-CO-R
If the alkyne is uneven, you get a combination of two
ketones, since the O can increase to either of the alkyne C atoms.
R-C≡C-R' + H₂O → R-CH₂-CO-R' + R-CO-CH₂-R'
So, for CH₃CH₂CH₂-C≡C-CH₂CH₃, the products are
CH₃CH₂CH₂-CH₂-CO-CH₂CH₃ and CH₃CH₂CH₂-CO-CH₂-CH₂CH₃
Their terms are heptan-3-one and heptan-4-one,
Answer:
Once you have identified the limiting reactant, you calculate how much of the other reactant it must have reacted with and subtract from the original amount.
Explanation:
1. Write the chemical equation.
2.Calculate the moles of product from the first reactant.
3.Calculate the moles of product from the second reactant.
4.Identify the limiting reactant and the excess reactant.
5.Calculate the mass of excess reactant used up.
6.Calculate the mass of unused excess reactant.
7.Calculate the mass of limiting reactant needed to react with the unused excess reactant.
Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g) From the balanced chemical equation, 2 moles of HCl is required to react with 1 mole of Zn Mass of Zn = 9.55 g Molar mass of Zinc = 65.41 g/mol Number of moles = mass / molar mass Moles of Zn = 9.55 / 65.41 = 0.146 mol Moles of HCl required = 2 x moles of Zn = 2 x 0.146 = 0.292 mol