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3 years ago

Help 6th grade science i will give brainliest FOOLISH ANSWERS WILL BE REPORTED

Chemistry

1 answer:

Feliz [49]3 years ago

8 0

Answer: my answer would be B

Explanation: if you look at the graph and see the distance and time, you can match it to one of the answers. Hope this helps

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8. What behavior do all liquid or plastic solids near a heat source exhibit? L

LuckyWell [14K]

Answer:

Explanation:

One of the properties of a liquid is that, it's particles move freely (not tightly packed) hence the reason for it's free flowing (no definite shape) when shaken in a container, unlike a solid whose particles are tightly packed with restricted/no movement and hence the reason for it's compactness and it's definite shape.

When a plastic solid (whose particle is tightly packed and have a restricted movement/no movement) is placed near a heat source, it's particles gains energy in the process and starts to move (though slightly free) and become less tightly packed hence the reason it is observed that plastic solids near a heat source melts.

From the above, it can be deduced that a liquid and a plastic solid near a heat source have there particles move freely (and not tightly packed) hence making the two substances flow freely with no definite shape.

7 0

3 years ago

QUESTION 14

AveGali [126]

Within each functional group, the boiling points of members of the group vary according to molecular weight. Therefore, one cannot deduce any functional group from boiling points.

Organic compounds are divided into families called homologous series. Each homologous series has a functional group common to all the members of the series. As a result of this, the chemical properties of all the members of the homologous series are similar.

However, the boiling points of the members of a homologous series vary according the their molecular weights. As such, boiling points can not be used as evidence to classify substances into any particular homologous series.

Summarily, one cannot deduce any functional group from physical properties.

Learn more: brainly.com/question/1078956

7 0

3 years ago

200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?

Ipatiy [6.2K]

M be molar concentration
V be volume

M1=0.845M
V1=200mL=0.2L
V2=0.6L
M2=?

$\\ \tt\rightarrowtail M1V1=M2V2$

$\\ \tt\rightarrowtail 0.845(0.2)=0.6M2$

$\\ \tt\rightarrowtail 0.169=0.6M2$

$\\ \tt\rightarrowtail M2=0.281M$

7 0

2 years ago

Given 2.91 moles of a gas in a 500 milliliter-container, if the temperature is found to be 31 degrees Celsius, what is the press

kari74 [83]

Use the PV = nRT equation T is in Kelvins = 31 + 273 = 304 K

P(0.5) = (2.91)(0.0821)(304)
P(0.5) = 72.6289
P = 145.25 atm or 1.45x10^2 atm

3 0

3 years ago

Read 2 more answers

Use the Henderson-Hasselbalch equation, eq. (3), to calculate the pH expected for a buffer solution prepared from this acid and

notka56 [123]

Answer:

$pH=4.56$

Explanation:

Hello there!

In this case, given the Henderson-Hasselbach equation, it is possible for us to compute the pH by firstly computing the concentration of the acid and the conjugate base; for this purpose we assume that the volume of the total solution is 0.025 L and the molar mass of the sodium base is 234 - 1 + 23 = 256 g/mol as one H is replaced by the Na:

$n_{acid}=\frac{0.2g}{234g/mol}=0.000855mol\\\\n_{base}= \frac{0.2g}{256g/mol}=0.000781mol$

And the concentrations are:

$[acid]=0.000855mol/0.025L=0.0342M$

$[base]=0.000781mol/0.025L=0.0312M$

Then, considering that the Ka of this acid is 2.5x10⁻⁵, we obtain for the pH:

$pH=-log(2.5x10^{-5})+log(\frac{0.0312M}{0.0342M} )\\\\pH=4.60-0.04\\\\pH=4.56$

Best regards!

6 0

2 years ago