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s344n2d4d5 [400]
3 years ago
15

a radio controlled airplane is moving at a velocity of 23 m/s. it accelerates to a velocity of 85 m/s in 9.3 seconds. what accel

eration did the airplane experience?
Chemistry
1 answer:
tatuchka [14]3 years ago
7 0

I will show you a method to find a velocity of anything:-


Find average velocity when acceleration is constant.

Set up an equation with position and time instead.

Find the distance between the start and end points.

Calculate the change in time.

Divide the total displacement by the total time.

Solve problems in two dimensions.

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The Lewis dot model of a metal atom has two dots. Which of the following is true about the atom?
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It is present in the second group of the periodic table

Explanation:

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Describe the measurements necessary to find the average speed of a moving train
pshichka [43]

Answer:

use the rule of speed

Explanation:

speed =distance over time

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What is the difference in atomic structure between Lead-205 and Lead-208?
Nataly_w [17]

Answer:

  the number of neutrons in the nucleus

Explanation:

The mass number 205 is the total number of protons and neutrons in the nucleus. Lead has 82 protons, so a mass number of 205 indicates a nucleus with 123 neutrons.

Similarly, the mass number 208 indicates a lead nucleus with 126 neutrons.

The difference in atomic structure is the difference in the number of neutrons in the nucleus.

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How many atoms are in 9.95 moles of iron?
zvonat [6]

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59.92 × 10²³ atoms are in 9.95 moles of iron

1.8 ×10²² molecules are in 0.03 moles of Carbon dioxide

1.19 moles are found in 7.20 x 10^23 atoms of platinum

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3 years ago
The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate =3.45 g\times \frac{32.5}{100}=1.121 mol

Moles of bicarbonate ion = \frac{1.121 g/mol}{61 g/mol}=0.01840 mol

HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0
3 years ago
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